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3 years ago

If the dimensions of a solid proportionally increase by a scale factor of , by what factor does the surface area increase?

2 answers:

8 0

There is not a scale factor provided.
rule of thumb

perimeter, length, etc.
1- dimensions scale factor increases (scale factor)^1
think of answers ft, yd, etc.

area
2-dimensional (l x w) each dimension will increase by the scale factor. in this example, scale factor of 2.....(2l x 2w) increase by 2^2 or 4
increased by (scale factor)^2, think of answers given as ft^2, yd^2

volume
3-dimensional (l x w x h), each dimension will increase by the scale factor. in this example, scale factor of 2.....(2l x 2w x 2h) increased by 2^3 or 8
increases by (scale factor)^3, think of answers given as ft^3, yd^3

Hope this helps!! Happy Studies.

weeeeeb [17]3 years ago

8 0

The answer is 25/4. hopefully his helps

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WILL MARK BRAINLEST <br> PLS SHOW STEP BY STEP

defon

Answer:

$\frac{225}{30}$ or $7\frac{1}{2}$

Step-by-step explanation:

$\frac{25*9}{3*10} = \frac{225}{30}$

hope this helped

sorry if im too late lol

8 0

3 years ago

PLSS HELPPP!! Given vector u equals 15 times open angled bracket cos 45 degrees comma sin 45 degrees close angle bracket comma w

aksik [14]

The answer to your question is the 2 one

3 0

2 years ago

what are the domain of the function what are the domain of the function y equal 2 start root 3x plus 4 end root?

inna [77]

Y=sqrt(3x+4)

3x+4 must be positive

3x+4>=0
Solving for x:
3x+4-4>=0-4
3x>=-4
3x/3>=(-4)/3
x>=-(4/3)

Domain of the function = [-(4/3), +Infinite)

5 0

4 years ago

1. Given points ????(3, −5) and ????(19, −1), find the coordinates of point ???? that sit 3/8 of the way along AB ,close to A th

Nastasia [14]

Answer: The required co-ordinates of point C are (9, -3.5).

Step-by-step explanation: We are given the points A(3, -5) and B(19, -1).

We are to find the co-ordinates of point C that sit 3/8 of the way along AB, where the point P is close to A than to B.

According to the given information, we have

$\dfrac{AC}{AB}=\dfrac{3}{8}\\\\\Rightarrow \dfrac{AC}{AC+BC}=\dfrac{3}{8}\\\\\Rightarrow 8AC=3AC+3BC\\\\\Rightarrow 5AC=3BC\\\\\Rightarrow AC:BC=3:5.$

So, point C divides the line segment AB in the ratio 3 : 5.

We know that

if a point Q divides a line segment joining the points S(a,b) and T(c,d), in the ratio m : n, then the co-ordinates of Q are

$\left(\dfrac{mc+na}{m+n},\dfrac{md+nb}{m+n}\right).$

Therefore, the co-ordinates of point C are

$\left(\dfrac{3\times19+5\times3}{3+5},\dfrac{3\times(-1)+5\times(-5)}{3+5}\right)\\\\\\=\left(\dfrac{57+15}{8},\dfrac{-3-25}{8}\right)\\\\=(9,-3.5).$

Thus, the required co-ordinates of point C are (9, -3.5).

3 0

4 years ago

1 1/2 x 2/1 1/3 Answer the problem and show your work.

devlian [24]

Answer: 1 / 2 x2 / 1 1 / 3 = 0.3333333333

Step-by-step explanation:

Divide: 11 / 2 = 5.5

Multiple: the result of step No. 1 * 2 = 5.5 * 2 = 11

Divide: the result of step No. 2 / 11 = 11 / 11 = 1

Divide: the result of step No. 3 / 3 = 1 / 3 = 0.33333333

7 0

3 years ago