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BlackZzzverrR [31]
3 years ago
14

If the dimensions of a solid proportionally increase by a scale factor of , by what factor does the surface area increase? 

Mathematics
2 answers:
shutvik [7]3 years ago
8 0
There is not a scale factor provided.
rule of thumb

perimeter, length, etc. 
1- dimensions scale factor increases (scale factor)^1
think of answers ft, yd, etc.

area     
2-dimensional (l x w)  each dimension will increase by the scale factor. in this example, scale factor of 2.....(2l x 2w)  increase by 2^2 or 4
increased by (scale factor)^2,  think of answers given as ft^2, yd^2

volume
3-dimensional  (l x w x h), each dimension will increase by the scale factor.  in this example, scale factor of 2.....(2l x 2w x 2h) increased by 2^3 or 8
increases by (scale factor)^3, think of answers given as ft^3, yd^3

Hope this helps!!  Happy Studies.

 
weeeeeb [17]3 years ago
8 0

The answer is 25/4. hopefully his helps

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Find an equivalent system of equations for the following system: 3x + 3y = 0 −4x + 4y = −8 3x + 3y = 0 7x − y = 8 3x + 3y = 0 −7
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Answer:

A.

3x + 3y = 0

7x − y = 8

Step-by-step explanation:

Given

3x + 3y = 0

-4x + 4y = -8

Required

Find the equivalent

To solve for the equivalent we simply solve for x and y in the given equation.

Subtract 3x from both sides in 3x + 3y = 0

3x - 3x + 3y = 0 - 3x

3y = -3x

Multiply both sides by ⅓

⅓ * 3y = -3x * ⅓

y = -x

Substitute -x for y in -4x + 4y = -8

-4x + 4(-x) = -8

-4x -4x = -8

-8x = -8

Multiply both sides by -⅛

-⅛ * -8x = -⅛ * -8

x = 1

Recall that y = -x

y = -1

So, we have that x = 1 and y = -1

We'll substitute these values in the list of options;

A.

3x + 3y = 0

7x − y = 8

7(1) - -(1) = 8

7 + 1 = 8 ----- This is equivalent

B.

3x + 3y = 0

−7x − y = 8

-7(1) - (-1) = 8

-7 + 1 = 8

-6 ≠ 8 .... This is not an equivalent expression

C.

3x + 3y = 0

−7x + 7y = 8

-7(1) + 7(-1) = 8

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-14 ≠ 8 .... This is also not an equivalent expression

D.

3x + 3y = 0

-4x + 7y = 8

-4(1) + 7(-1) = 8

-4 -7 = 8

-11 ≠ 8 -_- This is also not an equivalent expression

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