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Effectus [21]
4 years ago
10

Justify 2.010010001.....is an irrational number

Mathematics
2 answers:
ser-zykov [4K]4 years ago
8 0
No its rational....................

Ratling [72]4 years ago
7 0
A decimal expansion of a rational number either terminates or follows a repeating pattern of a *finite* sequence of digits.

Neither of these is the case here. The decimal expansion is obviously non-terminating, nor is the sequence of digits finite.

Writing the number as

2.010010001\ldots=1+1.010010001\ldots

and only considering the second number, you have the following sequence of digits: \{1,0,1,0,0,1,0,0,0,1,\ldots\}, where the nth term, starting with n=0 corresponds to the number 10^{-n}. The sequence can be described recursively by the recurrence

\begin{cases}a_0=1\\a_{n+1}=a_n+n+2&\text{for }n\ge1\end{cases}

and explicitly by a_n=\dfrac{n(n+3)}2.

This sequence is not periodic, and indeed diverges to \infty as n\to\infty. This means the number cannot be rational.
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