Answer:
4.5 % alloy
Step-by-step explanation:
Let x = amt of 30% alloy
The resulting total is to be 25 oz, therefore:
(25-x) = amt of 5% alloy:
A typical mixture equation:
.30x + .05(25-x) = .20(25)
.30x + 1.25 - .05x = 5 .30x - .05x = 5 - 1.25
.25x = 3.75
x = 3.75%2F.25
x = 15 oz of 30% alloy required
then
25-15 = 10 oz of 5% alloy:
Check solution
.30(15) + .05(10) = .20(25)
4.5 + .5 = 5
(180-14):2= 166:2= 83° (smaller angle)
(180-14):2+14= 166:2+14= 83+14= 97° (bigger angle)
Answer:
Step-by-step explanation:
Let's express all the given numbers as decimals:
nine tenths- 0.9
0.3
0.8
five tenths- 0.5
two tenths- 0.2
Ordering them from least to greatest:
two tenths, 0.3, five tenths, 0.8, nine tenths
The set X = { x , {x} } would, I think, fit the Bill
So its 2 elements