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OLga [1]
3 years ago
12

Help if you can please!!

Mathematics
1 answer:
rosijanka [135]3 years ago
6 0
<h3>Answer: Choice (B)</h3><h3>25b^2+40b+23</h3>

===================================================

Work Shown:

c(b) = 5b

h(b) = b+4

h(c(b)) = c(b)+4 ... replace every b with c(b)

h(c(b)) = 5b+4 ... replace c(b) on the right hand side with 5b

For the sake of simplicity, let's call "h(c(b))" as k

k = h(c(b))

k = 5b+4

that way we can use it later in the next section

---------------

a(b) = b^2 + 7

a(k) = k^2 + 7 ... replace b with k

a(k) = (5b+4)^2 + 7 ... plug in k = 5b+4

a(k) = 25b^2+40b+16+7 .... use FOIL rule

a(k) = 25b^2+40b+23

a( h(c(b)) ) = 25b^2+40b+23

In that last step, I replaced k with h(c(b)) so that we get to the original format your teacher wanted.

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Step-by-step explanation:

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6m < 300

___   ___

 6        6

m < 50

So the answers are numbers less than 50.

Which are the first four answers:

A, B, C, D

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3 years ago
The frequency of an AM radio is 1.4 x 106 hertz (cycles per second). Approximately, how many cycles are completed in a minute?
Vadim26 [7]
<span>There are 8,904 cycles per minute. This would be determining the amount of cycles per second, which is 148.4. After you know the amount per second, you can then multiply it by the time, which in this case is 60 seconds, or 1 minute. 148.4 cycles per second multiplied by 60 seconds is 8,904 cycles.</span>
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julsineya [31]

Monday and Tuesday because the second spot after the decimal point is the hundredths spot.

7 0
3 years ago
Write the equation of a line perpendicular to y=-12x+2 going through (0,-1)
DanielleElmas [232]

             \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

          <em>Write the equation of a line perpendicular to y=-12x+2 going </em>

<em>            through (0, -1)</em>

<em />

<em>      </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

        First, let's take a look at our provided information:-

  • A line \text{y=-12x+2}
  • A point (0, -1)
  • The line \text{y=-12x+2} is perpendicular to the line that goes through (0, -1)

     If two lines are perpendicular to each other, their slopes are opposite reciprocals of each other.

   So we take the slope of the given line, which is -12, change its sign from minus to plus:-

\Large\textit{12}

And now, We flip the number over:-

\Large\text{$\displaystyle\frac{1}{12}$}

Now that we've found the slope of the line, let's find its equation.

     The first step is to write it in point-slope form as follows:-

\longmapsto\sf{y-y_1=m(x-x_1)}

Replace letters with numbers,

\longmapsto\sf{y-(-1)=\displaystyle\frac{1}{12}(x-0)}

On simplification,

\longmapsto\sf{y+1=\displaystyle\frac{1}{12} (x-0)}

On further simplification,

\longmapsto\sf{y+1=\displaystyle\frac{1}{12} x}

Subtracting 1 on both sides,

\longmapsto\sf{y=\displaystyle\frac{1}{12} x-1}

\Uparrow\texttt{Our equation in slope-intercept form}

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

\rule{300}{1}

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Lera25 [3.4K]
2+4+2+4+2=16÷5=3.2 average
8 0
3 years ago
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