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OLga [1]
4 years ago
12

Help if you can please!!

Mathematics
1 answer:
rosijanka [135]4 years ago
6 0
<h3>Answer: Choice (B)</h3><h3>25b^2+40b+23</h3>

===================================================

Work Shown:

c(b) = 5b

h(b) = b+4

h(c(b)) = c(b)+4 ... replace every b with c(b)

h(c(b)) = 5b+4 ... replace c(b) on the right hand side with 5b

For the sake of simplicity, let's call "h(c(b))" as k

k = h(c(b))

k = 5b+4

that way we can use it later in the next section

---------------

a(b) = b^2 + 7

a(k) = k^2 + 7 ... replace b with k

a(k) = (5b+4)^2 + 7 ... plug in k = 5b+4

a(k) = 25b^2+40b+16+7 .... use FOIL rule

a(k) = 25b^2+40b+23

a( h(c(b)) ) = 25b^2+40b+23

In that last step, I replaced k with h(c(b)) so that we get to the original format your teacher wanted.

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Select the correct answer.
Nookie1986 [14]

Answer:

Correct option: C.

Step-by-step explanation:

(Assuming the correct function is R(x) = 2x^2 + 3x + 5)

To find the input value that gives the value of R(x) = 19, we just need to use this output value (R(x) = 19) in the equation and then find the value of x:

R(x) = 2x^2 + 3x + 5

19 = 2x^2 + 3x + 5

2x^2 + 3x -14 = 0

Solving this quadratic function using the Bhaskara's formula (a = 2, b = 3 and c = -14), we have:

\Delta = b^2 - 4ac = 9 + 112 = 121

x_1 = (-b + \sqrt{\Delta})/2a = (-3 + 11)/4 = 2

x_2 = (-b - \sqrt{\Delta})/2a = (-3 - 11)/4 = -3.5

So looking at the options, the input to the function is x = 2

Correct option: C.

3 0
3 years ago
25 POINTS AND BRAINLY(dont answer if u don't know it)
harkovskaia [24]
The expression that represents the density is D = h^2 - 4h + 20/pi h^2
6 0
3 years ago
Can i have some help i need to find the surface area​
makkiz [27]

Answer:

644ft^2

Step-by-step explanation:

Area of triangle=1/2bh

Area of square=l*l

so we have;

4 triangles with a base of 14ft and height of 16ft and 1 square with l=14ft

AreaTriangle=1/2(14ft)(16ft)=112ft*4=448ft^2

AreaSquare=14ft*14ft=196ft^2

Area Total=448ft+196ft=644ft^2

7 0
4 years ago
Find x and RS if S is between R and T <br>RS=6x,ST=12,and RT=72
sergij07 [2.7K]
Ah, ok

RST

so RS+ST=RT
6x+12=72
minus 12 both sides
6x=60
divide both sides by 6
x=10


x=10
6 0
4 years ago
Gerard concluded that the triangle with sides StartRoot 95 EndRoot feet, 8 feet, and StartRoot 150 EndRoot cannot be used as a b
Pachacha [2.7K]

Answer:

Check explanations for answer

Step-by-step explanation:

Here, we want to find out how Gerard came to the conclusion

For him to arrive at this conclusion, then we should consider the lengths given if they form a right triangle and are suitable for the building frame

From the lengths that we have

If we square the longest length, then the sum of the squares of the two other lengths should be the same as it is

This is in obedience to Pythagoras’ theorem

However, this does not hold

√(150)^2 is not equal to 8^2 + (√(95))^2)

and so since this does not work, then the triangle is not right-angled and cannot be use as the frame

3 0
3 years ago
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