All categories

3 years ago

Write the HTML code tags needed to create a simple webpage. Remember to include open and end tags.

Computers and Technology

1 answer:

podryga [215]3 years ago

6 0

Answer:

See below explanation

Explanation:

<!DOCTYPE html>

<html>

<head>

<title>Title of the document is kept here</title>

</head>

<body>

This is where the content of the document is placed

</body>

</html>

You might be interested in

Adam has decided to add a table in a Word doc to organize the information better. Where will he find this option? Insert tab, Il

RUDIKE [14]

He will have to navigate to the Insert Tab and then Click on Table option.

6 0

3 years ago

Read 2 more answers

Barat explains that if you have a cell that is the sales price of a given product, the value of which will change to produce the

Mice21 [21]

Answer Choices:

a.goal cell

b.constraint

c.changing cell

d.absolute cell

Answer:

c.changing cell

4 0

4 years ago

Write an algorithm to convert lengh of your house from cm to meter

sergiy2304 [10]

Answer:

cm = 1000;

meter = cm / 100.0;

kilometer = cm / 100000.0;

print("Length in meter = " ,

meter , "m");

print("Length in Kilometer = ",

kilometer , "km");

Explanation:

This is in Python, hope you enjoy!

8 0

3 years ago

Write a C++ program that computes an approximation of pi (the mathematical constant used in many trigonometric and calculus appl

Verizon [17]

Answer:

#include <iostream>

#include<cmath>

using namespace std;

int main()

{

double total = 0;

double check=1;

double ct=0;

double old=1;

while( fabs(total - old) > 0.00005 )

{

old=total;

total=total+check*4.0/(2.0*ct+1);

ct=ct+1;

check=0.0-check;

}

cout<<"Approximate value of pi is "<<total<<endl;

return 0;

}

Explanation:

Initialize all the necessary variables.

Run a while loop until the following condition is met.

fabs(total - old) > 0.00005

Inside the while loop calculate the total value.
Lastly, display the approximate value of pi.

3 0

4 years ago

Assume a program requires the execution of 50 x 106 FP instructions, 110 x 106 INT instructions, 80 x 106 L/S instructions, and

Molodets [167]

Explanation:

FP - $50 \times 10^6$

CPI - 1

INT - $110 \times 10^6$ ,

CPI - 1

I/S - $80 \times 10^6$ ,

CPI - 4

Branch - $16 \times 10^6$

CPI - 2

Clock Speed - $2 \times 10^9$

Time(old) = $\frac{50 x 10^6 + 110 x 10^6 + 4 x ( 80 x 10^6) + 2 x (16 x 10^ 6)}{2 x 10^9}$

Time(old) = $256 \times 10^ {-3}$

Time(new) = $\frac{256 \times 10^{-3}}{2}$

= $128 \times 10^{-3}$

= $\frac{CPI(new) x [50 x 10^6 + 110 x 10^6 + 4 x ( 80 x 10^6) + 2 x (16 x 10^ 6)]}{2 x 10^9}$

= $128 \times 10^{-3}$

CPI(new) = $\frac{-206}{50}$

= -4.12

3 0

3 years ago