3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions
F(8x+5)^-1=0.2
(8+5)^-1=0.077
5^-1=0.2
8x^-1=0.125
0.125-0.2=-0.075/0.2-0.125=0.075
Answer:
The number of horses that can eat 4 stacks of hay in 8 days = 56 horses
Step-by-step explanation:
The given parameters are;
The time it takes 16 horses to eat 5 stacks = 35 days
Therefore;
The time it takes 16 horses to eat 5/5 stacks (1 stack) = 35 days/5 = 7 days
The time it takes 16 horses to eat 1 stack of hay = 7 days
The time it takes 16 horses/16 to eat 1 stack of hay = 7 days × 16 = 112 days
Therefore;
The time it takes 1 horse to eat 1 stack of hay = 112 days
The time it takes 1 horse to eat 4 × 1 stack of hay = 112 days × 4 = 448 days
The time it takes 1 horse to eat 4 stacks of hay = 448 days
Therefore, given that (448 days)/(8 days/horse) = 56 horse, we have;
The number of horses that will eat 4 stacks of hay in 8 days = 56 horses.
Answer:
105.3%
Step-by-step explanation:
i use the is over of method so:
, multiply 79 x 100, then divide by 75.
Answer:
The correct option is (b).
Step-by-step explanation:
The solution of the given polynomial is :
x = 1/3 and y = -4
i.e.
Sum of roots = (1/3-4) = -11/3
Product of roots = (1/3)(-4) = -4/3
The quadratic equation is as follows :
Put all the values,
So, the correct option is (b).
