Question

Given the following functions f(x) and g(x), solve f over g (−5) and select the correct answer below:

Answer 1

Plug -5 into both of them and divide:

$\sf\dfrac{2x-20}{x-1}$

$\sf\dfrac{2(-5)-20}{-5-1}$

Simplify:

$\sf\dfrac{-10-20}{-6}$

$\sf\dfrac{-30}{-6}$

$\boxed{\sf 5}$

Answer 2

Answer:

Option b is correct.

$(\frac{f}{g})(-5)$ = 5

Step-by-step explanation:

Given the functions:

$f(x)=2x-20$

$g(x)=x-1$

Solve: $(\frac{f}{g})(-5)$

$(\frac{f}{g})(x) = \frac{f(x)}{g(x)}$

Substitute the given function we have;

$(\frac{f}{g})(x) = \frac{2x-20}{x-1}$

Put x = -5 we have;

$(\frac{f}{g})(-5) = \frac{2(-5)-20}{-5-1} =\frac{-10-20}{-6}=\frac{-30}{-6} = 5$

therefore, the value of $(\frac{f}{g})(-5)$ is 5.