Margot used

What is the measure of KPN? A. 35° B. 50° C. 60° D.65° E. 70°

luda_lava [24]

Answer:

Option (B)

Step-by-step explanation:

From the picture attached,

NL and KM are the two lines intersecting at a point P.

Therefore, ∠KPN ≅ LPM [Vertical angles]

In ΔPLM,

m∠LPM + m∠PML + m∠PLM = 180° [Property of a triangle]

m∠LPM + 70° + 60° = 180°

m∠LPM + 130° = 180°

m∠LPM = 180° - 130°

m∠LPM = 50°

Therefore, m∠KPN = 50° [vertical angles]

Option (B) will be the correct option.

3 0

3 years ago

Does this graph show a function? Explain how you know.

Bess [88]

Answer:

a. no the graph fails the vertical line test

4 0

3 years ago

Read 2 more answers

In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study

DIA [1.3K]

Answer:

$z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055$

The p value can be calculated from the alternative hypothesis with this probability:

$p_v =2*P(Z>2.055)=0.0399$

And the best option for this case would be:

C. between 0.01 and 0.05.

Step-by-step explanation:

Information provided

$X_{1}=1642$ represent the number of smokers from the sample in 1995

$X_{2}=1415$ represent the number of smokers from the sample in 2010

$n_{1}=4276$ sample from 1995

$n_{2}=3908$ sample from 2010

$p_{1}=\frac{1642}{4276}=0.384$ represent the proportion of smokers from the sample in 1995

$p_{2}=\frac{1415}{3908}=0.362$ represent the proportion of smokers from the sample in 2010

$\hat p$ represent the pooled estimate of p

z would represent the statistic

$p_v$ represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

The statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374$

Replacing the info given we got:

$z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055$

The p value can be calculated from the alternative hypothesis with this probability:

$p_v =2*P(Z>2.055)=0.0399$

And the best option for this case would be:

C. between 0.01 and 0.05.

7 0

3 years ago

The maximum weight of a suitcase that an airline allows is 50 pounds. For every 1 pound, there is approximately 0.45 kilograms.

Marta_Voda [28]

Answer: 22.5 kg

Step-by-step explanation:

You did not attach a question, so I'm going to assume that it is asking for the maximum weight of a suitcase in kilograms.

3 0

2 years ago

Please answer this correctly

Lynna [10]

Answer:

557

Step-by-step explanation:

l x w

13x24

13x7

22x7

557

4 0

3 years ago