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4 years ago

Find the equation of a plane that is perpendicular to the vector −4i⃗ −4j⃗ −k⃗ and passing through the point (−2,−5,5)

Mathematics

1 answer:

vredina [299]4 years ago

5 0

hello ....

the equation of a plane that is ; ax+by+cz +d =0

the vector perpendicular to this plane is : V(a,b,c)

in this exercice ; a = -4 b= -4 c = -1

then: the equation of a plane that is ; -4x-4y-z +d =0

but the plane passing through the point (−2,−5,5) :

-4(-2)-4(-5)-(5) +d =0

23+d =0

d =-23

the equation of a plane is : -4x-4y-z-23 =0

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3 years ago

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3 years ago

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3 years ago

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3 years ago

George hiked from the top of a hill to the valley floor. The elevation at the top of the hill is 127 feet above sea level. The v

notsponge [240]

Answer:

The elevation of the rest stop is 37.5 feet above sea level.

Step-by-step explanation:

Given that the elevation at the top of the hill is 127 feet above sea level and The valley floor is 52 feet below sea level.

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$52 + x = 89.5 \\\\\Rightarrow x =89.5-52 \\\\$

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3 0

3 years ago