First of all, we can observe that
So the expression becomes
This means that the expression is defined for every 
Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask
Since we can't accept 3 as an answer, the actual solution set is
![(-\infty,-2] \cup [2,3) \cup (3,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-2%5D%20%5Ccup%20%5B2%2C3%29%20%5Ccup%20%283%2C%5Cinfty%29)
Domain is the first set of numbers or x
52, 72, 86 and 105
the y coordinates are the range
<h2>Evaluating Composite Functions</h2><h3>
Answer:</h3>
<h3>
Step-by-step explanation:</h3>
We can write how 
will be defined but that's too much work and it's only useful when we are evaluating with many inputs.
First let's solve for 
first. As you read through this answer, you'll get the idea of what I'm doing.
Given:
Solving for :
Now we can solve for 
, since 
, 
.
Given:
Solving for 
:
Now we are can solve for 
. By now you should get the idea why 
.
Given:
Solving for :
Answer:
-1
Step-by-step explanation:
x^2 – 8
-----------
x + 6
Let x = -2
(-2)^2 – 8
-----------
-2 + 6
Exponents first
4 – 8
-----------
-2 + 6
Then complete the numerator and denominator
-4
-----
4
Then divide
-1
Answer:
Step-by-step explanation:
Opposite angles in an inscribed quadrilateral are supplementary, so ...
∠B +∠D = 180°
(3x -4) +(2x -6) = 180
5x = 190 . . . . . . . . . . . add 10, collect terms
x = 38 . . . . . . . . . . . . . divide by 5
∠D = 2(38) -6 = 70
∠B = 180 -70 = 110
The measures of angles B and D are 110° and 70°, respectively.
