Answer:
36.36%
Explanation:
Return on investment is given as;
Profit / Cost of goods sold × 100%
Given that profit is $12,000 and sales is $45,000 ;
Cost of goods sold
= $45,000 - $12,000
= $33,000
Therefore, return on investment is
= 12,000 / 33,000 × 100%
= 36.36%
That type of paper is called carbonless copy paper, or non-carbon copy paper, or NCR Paper (= no carbon required).
You use it when you don't want to copy the same thing twice, or three times, or more, so you just take this paper, with some papers underneath it, and write on the first paper, and everything you write will be transferred onto those papers below it.
The difference between the monthly payment of R and S is equal to $48.53 by following the compound interest formula. Thus, Loan R's monthly loan amount is greater than Loan S.
<h3>What is a Compound interest loan?</h3>
Combined interest (or compound interest) is the loan interest or deposit calculated based on both the original interest and accrued interest from earlier periods.
![\rm\,For\,R\\\\P = \$\,17,550\\r\,= 5.32\%\\Time\,= n= 7\,years\\Amount\,paid= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\=[ 17,550 (1+\dfrac{5.32}{100\times12})^{7\times12} ]\\= [ 17,550 (\dfrac{12.0532}{12})^{84} ]\\\\= [ 17,550 (1.00443^{84} ]\\\\= \$ 25,440.48\\\\Total\,monthly\,payment = \rm\,\dfrac{25,440.48}{84}\\\\= \$\, $302.86\\\\](https://tex.z-dn.net/?f=%5Crm%5C%2CFor%5C%2CR%5C%5C%5C%5CP%20%3D%20%5C%24%5C%2C17%2C550%5C%5Cr%5C%2C%3D%205.32%5C%25%5C%5CTime%5C%2C%3D%20n%3D%207%5C%2Cyears%5C%5CAmount%5C%2Cpaid%3D%20%5BP%281%2B%5Cdfrac%7Br%7D%7B100%5Ctimes12%7D%29%5E%7Bn%5Ctimes12%7D%20%5D%5C%5C%3D%5B%2017%2C550%20%281%2B%5Cdfrac%7B5.32%7D%7B100%5Ctimes12%7D%29%5E%7B7%5Ctimes12%7D%20%5D%5C%5C%3D%20%5B%2017%2C550%20%28%5Cdfrac%7B12.0532%7D%7B12%7D%29%5E%7B84%7D%20%5D%5C%5C%5C%5C%3D%20%20%5B%2017%2C550%20%281.00443%5E%7B84%7D%20%5D%5C%5C%5C%5C%3D%20%5C%24%2025%2C440.48%5C%5C%5C%5CTotal%5C%2Cmonthly%5C%2Cpayment%20%3D%20%5Crm%5C%2C%5Cdfrac%7B25%2C440.48%7D%7B84%7D%5C%5C%5C%5C%3D%20%5C%24%5C%2C%20%24302.86%5C%5C%5C%5C)
![\rm\,For\,S =\\\\P=\,\$ 15,925\\r\,= 6.07\%\\T=n= 9\,years\\\\Amount\,paid\,= [P(1+\dfrac{r}{100\times12})^{n\times12} ]\\\\\= [15,925(1+\dfrac{0.0607}{12})^{9\times12} ]\\\\\\= [15,925(1+\dfrac{0.0607}{12})^{108} ]\\\\=[15,925(1.7247.84)} ]\\\\\= \$27,467.19\\\\Total\,monthly\,payment =\dfrac{\rm\,\$\,27,469.19}{108}\\\\= \$ 254.326\\\\](https://tex.z-dn.net/?f=%5Crm%5C%2CFor%5C%2CS%20%3D%5C%5C%5C%5CP%3D%5C%2C%5C%24%2015%2C925%5C%5Cr%5C%2C%3D%206.07%5C%25%5C%5CT%3Dn%3D%209%5C%2Cyears%5C%5C%5C%5CAmount%5C%2Cpaid%5C%2C%3D%20%5BP%281%2B%5Cdfrac%7Br%7D%7B100%5Ctimes12%7D%29%5E%7Bn%5Ctimes12%7D%20%5D%5C%5C%5C%5C%5C%3D%20%5B15%2C925%281%2B%5Cdfrac%7B0.0607%7D%7B12%7D%29%5E%7B9%5Ctimes12%7D%20%5D%5C%5C%5C%5C%5C%5C%3D%20%5B15%2C925%281%2B%5Cdfrac%7B0.0607%7D%7B12%7D%29%5E%7B108%7D%20%5D%5C%5C%5C%5C%3D%5B15%2C925%281.7247.84%29%7D%20%5D%5C%5C%5C%5C%5C%3D%20%5C%2427%2C467.19%5C%5C%5C%5CTotal%5C%2Cmonthly%5C%2Cpayment%20%3D%5Cdfrac%7B%5Crm%5C%2C%5C%24%5C%2C27%2C469.19%7D%7B108%7D%5C%5C%5C%5C%3D%20%5C%24%20254.326%5C%5C%5C%5C)
The difference between the monthly payment of R and S is equal to $48.53.
Hence, Loan R's monthly payment is greater than the loan's monthly payment by $48.53
To learn more about Compound interest, refer to the link:
brainly.com/question/14331235
Answer: Publicity
Explanation:
From the question, we are told that a small agrichemical laboratory with a very small marketing budget develops a seed that produces grass, which grows two-inches high and no higher.
Since the laboratory has a small marketing budget, the promotional element it can use to let others know about its discovery will be publicity.
Through publicity, the company can give out vital information about its new discovery. By doing this, the public will be aware of the innovation. Publicity is a marketing and promotion component.
Answer:
Quantity discounts can be taken advantage of for large lot sizes.
Explanation:
The EOQ model assumptions:
the order of one item does not intervene with the other.
The order will arrive without delay and with a specific amount of goods.
no losses or damage in transit
The EOQ does not consider the discount for large lot size, their formula does not consider the value of the goods:

Its use: Demand of the good
cost of Setup, or ordering cost.
and Holding cost, the cost of keeping the inventory
There is no variable to account for discounts for order size in this method