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andrew11 [14]
3 years ago
11

Answer 7 and 8 2 questions for brainliest answers UGRENT HELP NOW!!!!!

Mathematics
2 answers:
hjlf3 years ago
8 0
The answer to 7 is 4 and the answer to 8 is 2.7
Luba_88 [7]3 years ago
4 0
7. answers is 4
8. the answer is 2.7 ........can i get brainliest? please?
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Quadrilateral KMPT is dilated by a scale factor of 3/4 to create K'M'P'T'. The perimeter of quadrilateral KMPT is x units. What
777dan777 [17]

Answer:

B) \frac{3}{4} x units

Step-by-step explanation:

Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:

Perimeter of a rectangle = 2 (l + b)

where: l is the length = 12 units and b is the breadth = 8 units. So that:

Perimeter of KMPT = 2 (12 + 8)

                               = 40 units

Dilating KMPT by a scale factor of \frac{3}{4} would create K'M'P'T' of dimensions; \frac{3}{4} × 12 units by \frac{3}{4} × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.

Perimeter of K'M'P'T' = 2 (l + b)

                                  = 2(9 + 6)

                                  = 30 units

Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be  \frac{3}{4} × perimeter of KMPT.

Therefore, if the perimeter of KMPT is x units, then;

         perimeter of K'M'P'T' = \frac{3}{4} * x units

                                            = \frac{3}{4}x units

6 0
3 years ago
I need help from you guys I have to teach in class on friday and I'm in 7th grade what can I teach help you guys anything like p
anygoal [31]
Have you learned about the Pythagorean theorem? a² + b² = c² . . . you should teach them about this.
7 0
3 years ago
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What are the real zeroes of x3 + 6 x2 – 9x - 54?
o-na [289]

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of x^3+6x^2-9x-54

Solving

x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)

Taking x^2 common from first 2 terms and -9 from last two terms we get

=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\

Taking (x+6) common

(x+6)(x^2-9)\\

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

=(x+6)((x)^2-(3)^2)\\=(x+6)(x+3)(x-3)

Putting it equal to zero,

(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\,  x=3

So, Option B 3,-3,-6 is correct.

7 0
2 years ago
Which statement describes the system of equations?
Strike441 [17]

Answer:

x+2y=2.....(1)

x-2y=2......(2)

(substrate 1 in 2

x=2

substitutes x in 1

2+2y=2

4y=2

y=4/2

y=2

8 0
2 years ago
The table of values shows the number of touchdown passes that a quarterback threw in each of his first five football games of th
kvv77 [185]
If x is the game number, and y is the amount of touchdown passes for that specific game number, then (5,3) represents the idea that the quarter back threw y = 3 touchdown passes for game number x = 5

So the answer is choice D. This is the only ordered pair that comes from the given table. Something like (2,4) isn't true because the quarterback threw 1 touchdown pass (not 4) in game two.
3 0
2 years ago
Read 2 more answers
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