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3 years ago

X^2-6x+9 factor the expression

Mathematics

1 answer:

nika2105 [10]3 years ago

5 0

(X-3)(X-3)
9 can be divided by 3
-6= -3 - 3

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Y=-4x-5 and y=-4x+1<br> Many solitions, one solution, or no solution

GuDViN [60]

There will be no solutions because the lines have the same slope (-4) meaning they are parallel to each other and will not cross.

Hope this helps!!

8 0

3 years ago

The formula for wind chill C (in degrees Fahrenheit) is given by C = 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16 where v is th

Diano4ka-milaya [45]

Answer:

dC = 2.44

Relative error = 19%

Step-by-step explanation:

$C = 35.74 + 0.6215*T - 35.75*v^(0.16) + 0.4275*T*v^(0.16)$

Δv = 3 ; ΔT = 1 , v = 23, T = 8

Use differential Calculus

$dC = Cv.dv + Ct.dt$

$Cv = dC/dv = -5.72*v^(-0.84) + 0.0684*T*v^(-0.84)\\Ct = dC/dT = 0.6215 + 0.4275*v^(0.16)\\dC = modulus (Cv.dv) + modulus (CT.dT)\\dC = (-5.72*v^(-0.84) + 0.0684*T*v^(-0.84))* 3 + (0.6215 + 0.4275*v^(0.16))*1\\dC = 2.44$

Relative Error

dC / C @(T = 8, v=23) * 100 = 19 %

8 0

3 years ago

Consider the equation below.

Kamila [148]

Answer:

Option (1)

Step-by-step explanation:

$\text{log}_4(x + 3)=\text{log}_2(2 + x)$

$\text{log}_4(x + 3)=\frac{\text{log}_{10}(x+3)}{\text{log}_{10}4}$

$\text{log}_2(2 + x)=\frac{\text{log}_{10}(2+x)}{\text{log}_{10}2}$

System of equations can be written as,

$y_1=\text{log}_4(x + 3)=\frac{\text{log}_{10}(x+3)}{\text{log}_{10}4}$

$y_2=\text{log}_2(2 + x)=\frac{\text{log}_{10}(2+x)}{\text{log}_{10}2}$

Therefore, system of equations given in Option (1) is the correct option.

4 0

3 years ago

Which of the following are solutions to the equation below?

34kurt

Answer:

B. 4

Step-by-step explanation:

Rearrange the equation so that is in the form (ax² + bx + c = 0).

6x² - 3x + 36 = 5x² + 10x

x² - 3x + 36 = 10x

x² - 13x + 36 = 0

Now, factor the equation and solve for x.

x² - 13x + 36 = 0

(x - 4)(x - 9) = 0

x - 4 = 0

x = 4

x - 9 = 0

x = 9

The solutions to the equation are 4 and 9. The correct answer choice is B.

6 0

2 years ago

Read 2 more answers

Ralph read 1/8 of his book. what fraction of the book does he still have left to read?

Andreas93 [3]

Ralph still needs to read 7/8

4 0

3 years ago