identifiy an equation in point slope form for the line perpendicular to y=3x+5 that passes through (4,-1)
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<h3>Answer ↓</h3>
y=-2x+5
<h3>Calculations ↓</h3>First of all we need to determine the slope of the line perpendicular to y = 1/2x - 5 .
The slopes of perpendicular lines are opposite reciprocals.
So we take 1/2 , turn it over , and change it's sign :
The slope of the line perpendicular to y = 1/2x-5 is -2 .
Since we're also given a point that the line crosses , we can write the line's equation in point - slope form :
y-y₁=m(x-x₁)
y-7=-2(x-(-1)
y-7=-2(x+1)
Now convert to slope intercept :
y-7=-2x-2
add 7 on both sides :
<h3>y = -2x+5</h3>