One car 1c
six bicycles 6b
two motorcycles
1c+6b+2m=9cbm
I think this is right but its been forever since i had to do these so
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
__
a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
For the answer to the question above asking w<span>hich of the following is true for the rational function f(x) = x-4/x^2-16?
The answer is
</span><span>g(x)=2 / x^2-16 </span>
<span>g(x) = 2 /(x+4)(x-4) </span>
<span>setting the denominator to 0, the vertical asymptotes are x = 4 and x = -4
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
Well I have more than 4 but whatever....
2 x 420
3 x 280
4 x 210
5 x 168
6 x 140
7 x 120
8 x 105
10 x 84
12 x 70
14 x 60
15 x 56
20 x 24
21 x 40
24 x 35
28 x 30
2 x 2 x 210
2 x 3 x 140
2 x 5 x 84
2 x 7 x 60
3 x 5 x 56
3 x 7 x 40
5 x 7 x 24
2 x 2 x 2 x 105
2 x 2 x 3 x 70
2 x 2 x 5 x 42
2 x 2 x 7 x 30
2 x 3 x 5 x 28
2 x 3 x 7 x 20
3 x 5 x 7 x 8
2 x 2 x 2 x 3 x 35
2 x 2 x 2 x 5 x 21
2 x 2 x 2 x 7 x 15
2 x 2 x 3 x 5 x 14
2 x 2 x 3 x 7 x 10
2 x 3 x 4 x 5 x 7
<span>2 x 2 x 2 x 3 x 5 x 7</span>
Hope I Helped You!!! :-)
Have A Good Day!!!
Answer:
14,181
Step-by-step explanation:
Let the total population of seal pups =p
Ratio of Tagged to Total seal pups observed is given as:
200:600
Population of Tagged to Total Population therefore is:
4727: p
Equating both ratios
200:600=4727:p
200/600=4727/p
200 X p= 4727 X 600
p = (4727 X 600)/200
p=14,181
The total population of fur seals pups is 14,181
