2 years ago

How to answer this problem

Mathematics

1 answer:

ddd [48]2 years ago

8 0

the solution is in pic .....base area is l×b and height is h

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Select all the expressions which are equivalent to -4/3p - 2/5

AVprozaik [17]

Answer

-2/5 -4/3 p and -4/3p+ (-2/5)

Step-by-step explanation:

those two are the only answers that has both parts of the expressions as negative.

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3 years ago

In 687,332,195, how is the value of the three in the ten thousands place related to the value of the 3 in the hundred thousands

olganol [36]

In this case, the value of the first 3 (the ten-thousands) has a value of 30,000. The 3 next to it, in the hundred-thousands place, has a value of 300,000. To compare the two, the 3 on the right has a value one-tenth as much as that on the left.

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3 years ago

Read 2 more answers

Complete the following a) 3/5 = ?/20 b) ?/6 = 25=30

vlada-n [284]

Answer:

a) 3/5=12/20

b)5/6=25/30

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2 years ago

The price of cappuccinos is $5.00 each. The price of pistachios is $1.00 per pound. If Curtiss has income of $32.00 and purchase

lutik1710 [3]

Answer:

curtiss can buy 7 pounds of pistachios

Step-by-step explanation:

5 cappuccinos x $5 = 25, 32 - 25=7

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2 years ago

Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 5.00. What should be the length of B⃗ so that th

creativ13 [48]

Answer:

Length of B is 7.4833

Step-by-step explanation:

The vector sum of A and B vectors in 2D is

$C=A+B=(a_1+b_1,a_2+b_2)$

And its magnitude is:

$C=\sqrt{(a_1+b_1)^2+(a_2+b_2)^2} =9$

Where

$a_1=Asinx$

$a_2=Acosx$

$b_1=Bsin(x+90)$

$b_2=Bcos(x+90)$

Using the properties of the sum of two angles in the sin and cosine:

$b_1=Bsin(x+90)=B(sinx*cos90+sin90*cosx)=Bcosx$

$b_2=Bcos(x+90)=B(cosx*cos90-sinx*sin90)=-Bsinx$

Sustituying in the magnitud of the sum

$C=\sqrt{(Asinx+Bcosx)^2+(Acosx-Bsinx)^2} =9$

$C=\sqrt{A^2sin^2x+2ABsinxcosx+B^2cos^2x+A^2cos^2x-2ABsinxcosx+B^2sin^2x} =9$

$C=\sqrt{A^2(sin^2x+cos^2x)+B^2(cos^2x+sin^2x)}$

$C=\sqrt{A^2+B^2} =9$

Solving for B

$A^2+B^2 =9^2$

$B^2 =9^2-A^2$

Sustituying the value of the magnitud of A

$B^2=81-5^2=81-25=56$

$B= 7. 4833$

8 0

3 years ago