We have been given that a circle of a certain radius has an area which is numerically 5 times the value of the circumference. We are asked to find the radius of the circle.
We know that area of circle with a radius of r units is
.
We know that circumference of a circle is
.
5 times the value of circumference would be
.
Now we will equate 5 times circumference with area as:

Let us solve for r.



Therefore, the radius of the circle would be 10 units.
Answer:
class boundaries are the end points of an open interval which contains the class interval such that the lower class boundary (LCB) is the LCL minus one-half the tolerance and the upper class boundary (UCB) is the UCL plus one -half the tolerance.
C, A, B
A’s rate if change:
3
B’s rate of change:
(10 - 0) / (-2 - (-4)) = 10 / 2
5
C’s rate of change:
1