All categories

2 years ago

Algebra one slope-intercept form

Mathematics

2 answers:

Oksana_A [137]2 years ago

6 0

Answer:

equation: y = -1

Given:

slope of 0

coordinates: ( 3 , -1 )

solve for equation:

y - y₁ = m(x-x₁)

y - (-1) = 0(x-3)

y + 1 = 0

y = -1

Makovka662 [10]2 years ago

3 0

(3,-1)

Equation in point slope form

$\\ \rm\hookrightarrow y+1=0(x-3)$

$\\ \rm\hookrightarrow y+1=0$

Equation in y=mx+b form

$\\ \rm\hookrightarrow y=-1$

You might be interested in

Elly and Drew work together to collect data to estimate the percentage of their classmates who own a particular brand of shoe. U

ladessa [460]

Answer:

d. The width of Elly's interval will be less than the width of Drew's interval.

Step-by-step explanation:

The confidence level and the width of the confidence interval are direct proportional. This means that a confidence interval with a higher confidence level has a higher width.

For example, a 99 percent confidence interval is wider than a 90 percent confidence interval.

The midpoint of the confidence interval is the mean of the population, no matter the confidence level.

In this problem, we have that:

Elly: 90 percent CI

Drew: 99 percent CI

The correct answer is:

d. The width of Elly's interval will be less than the width of Drew's interval.

4 0

3 years ago

Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give

frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$

using the equation of line:

$(y-y_1)=m(x-x_1)$

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

$(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\$

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

3 0

2 years ago

Name two integers that have a product between -10 and -15

umka2103 [35]

A product means when they are multiplied together.
I.e. The product of 3 and 4 is 12, because 3 * 7 = 4
i.e. The product of -4 and + 8 is 4, because -4 * 8 = -36

An integer means a whole number like 1, 2, 3, 4, 5, or -1, -2, -3, -4.
i.e. 3.2 is NOT AN INTEGER since there is a decimal

Two integers that have a product between -10 and -15
> Can be -6 and +2 which the product is -12 <------- (-6 * +2)
> Can be -7 and +2 which the product is -14 <------- (-7 * -21)
So an answer would be
"-6 and +2" are integers which have a product between -10 and -15

6 0

3 years ago

What is a reasonable estimate for the volume of a number cube: 8 cm3, 27 in?, or 1 ft??

LuckyWell [14K]

Answer:

just beweve

Step-by-step explanation:

3 0

2 years ago

Work out 27 ÷ 9 + 9 Work out 4 + 5 x 3 Work out -9 + -4 ) Work out 9 - -5

san4es73 [151]

Answer:

1. 27/9=3+9=12

2. 4+5x3=5x3=15+4=19

3. -9+-4=-13

4. 9--5=14

7 0

3 years ago

Read 2 more answers