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Sindrei [870]
3 years ago
14

X increased by 10 divided by 4

Mathematics
1 answer:
Eddi Din [679]3 years ago
4 0

Answer:

<em><u>\frac{x+10}{4}</u></em>

Step-by-step explanation:

First add 10 to x which equals x +10

Now divide it by 4 you get <em><u>\frac{x+10}{4}</u></em>

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Simplify the expression enter the answer in the box 5 1/6 - 7 1/3
OlgaM077 [116]
Hi hope this helps! Answer in the picture

5 0
3 years ago
Is (the fraction in the photo) rational or irrational?
love history [14]

Answer:

Irrational

Step-by-step explanation:

The square root of 2 is an irrational number as it is: ≈ 1.41. When you divide the square root of 2 by 3, it's still irrational: 0.47140452...

3 0
3 years ago
I need help finding the values of the last boxes shown in the image.
Bingel [31]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid revolution on the X-axis?</h3>

The volume of a solid is the degree of space occupied by a solid object. If the axis of revolution is the planar region's border and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

In the graph, the given straight line passes through two points (0,0) and (2,8).

Therefore, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

where:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Thus, from the graph let assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8), we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

  • y = 0
  • x = 2
  • y = 4x

Similarly, the change in polar coordinates is:

  • x = rcosθ,
  • y = rsinθ

where;

  • x² + y² = r²  and dA = rdrdθ

Now

  • rsinθ = 0   i.e.  r = 0 or θ = 0
  • rcosθ = 2 i.e.   r  = 2/cosθ
  • rsinθ = 4(rcosθ)  ⇒ tan θ = 4;  θ = tan⁻¹ (4)

  • ⇒ r = 0   to   r = 2/cosθ
  •    θ = 0  to    θ = tan⁻¹ (4)

Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

#SPJ1

5 0
2 years ago
Which expression is equivalent to<br> 32x8, 10?
diamong [38]

Answer:

480

Step-by-step explanation:

8x4=32

8x8=64

32x4=128

32x8=256

256+128+64+32=480

5 0
3 years ago
What is 5 + 5 + 5 + 5 + 6 + 7 + 5 + 6 + 4 + 4+ 4 + 6+ 3 + 3 + 1 + 9?
elena-14-01-66 [18.8K]

Answer:

5,555,675,644,463,319

Step-by-step explanation:

plz mark brainly

                                                         JK 78 LOL

7 0
3 years ago
Read 2 more answers
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