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2 years ago

Solve the inequality and enter your solution as an inequality in the box below.

Mathematics

2 answers:

PSYCHO15rus [73]2 years ago

8 0

Answer:

x > -10

Step-by-step explanation:

2 + x > -8

x > -8 - 2

x > -10

Crank2 years ago

4 0

Answer:

x>-10

Step-by-step explanation:

2+x-2>-8-2

x>-10

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Anyone know this? thank you

PSYCHO15rus [73]

Answer:

Exact form: 8 $\sqrt[4]{8}$

Decimal form: 13.45434264......

Hoped I Helped

4 0

4 years ago

Math lottssssss offf points

yan [13]

Constant of Proportionality = d/t = 90/2 = 45 mph

In short, Constant of Proportionality would be: 45 miles per hour.

Here, d/t = 45
d = 45t

In short, Your Equation would be: d= 45t

Hope this helps!

5 0

3 years ago

PLEASE HELP ASAP

Dafna1 [17]

Answer:

Step-by-step explanation:

27.068

28.08

28.15

29.94

6 0

2 years ago

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Can someone help me in this plssss I really need it

kompoz [17]

Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$

$\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}$

6 0

4 years ago

The solution to this system of equations lies between the x-values -2 and -1.5. At which x-value are the two equations approxima

drek231 [11]

Hello,
$\left \{ {{y= \dfrac{1}{x+2} } \atop {y=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {\dfrac{1}{x+2}=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x+2= \dfrac{1}{x^2+2} }} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x= \dfrac{1}{x^2+2} -2}} \right. \\\\


$
x=-1.81053571 and y=<span> 5,27803957 </span>

Download xls

3 0

3 years ago

Read 2 more answers