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3 years ago

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

Mathematics

1 answer:

nata0808 [166]3 years ago

6 0

Answer:

2) The second option (the bag)

8) 36 desserts

9) HH, HT, TT, TH: 1/4

Step-by-step explanation:

O - Not certain, it is possible to choose a green marble

O - Certain, all the numbers in the bag are less than 100, so the one you choose must be less than 105

O - Not certain, the spinner will not always land on the 10th letter of the alphabet

O - Not certain, the sum of the number cubes will not always be 12, depending on the number you roll

Size: Small cup, Large cup, Regular cone, Waffle cone

Flavors: Vanilla, Cookies & Cream, Mint Chocolate

Toppings: Fudge, Sprinkles, Caramel sauce

With a small cup:

Small cup, Vanilla, Fudge

Small cup, Vanilla, Sprinkles

Small cup, Vanilla, Caramel sauce

Small cup, Cookies & Cream, Fudge

Small cup, Cookies & Cream, Sprinkles

Small cup, Cookies & Cream, Caramel sauce

Small cup, Mint chocolate, Fudge

Small cup, Mint chocolate, Sprinkles

Small cup, Mint chocolate, Caramel sauce

There are 9 options with a small cup

There are 4 possibilities for types of cups

Multiply

4 * 9

The question is asking what would the sample space be of flipping a coin 2 times. You will not always alternate (heads, tails, heads, tails) when flipping a coin. This means that all of the possibilities are HH, HT, TT, TH.

Chance of getting heads = 1/2

Chance of getting tails = 1/2

Chance of getting 2 heads (divide by 2) = 1/4

Chance of getting 2 tails = 1/4

HH, HT, TT, TH: 1/4

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Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

2 years ago

Permutations of the word "Congratulations"

Mice21 [21]

Answer:

There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is 14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is 14!/(23)=10,897,286,400

5 0

2 years ago

Which of the following is a polynomial with roots 4, 6, and −7?

aleksklad [387]

Try plugging in 4,6, and -7 into the x's

8 0

2 years ago

Read 2 more answers

Will mark brainlist for anyone who answers these parts correctly and properly showed their work.

dalvyx [7]

Answer:

The rise is -5 the run is 4

Step-by-step explanation:

Slope (m) =

ΔY

ΔX

-5

-1.25

θ =

arctan(

ΔY

) + 360°

ΔX

308.65980825409°

ΔX = 2 – -2 = 4

ΔY = -1 – 4 = -5

Distance (d) = √ΔX2 + ΔY2 = √41 = 6.4031242374328

Equation of the line:

y = -1.25x + 1.5

y =

When x=0, y = 1.5

When y=0, x = 1.2

Please give brainliest PLZPLZ

I really hope this helps have a beautiful day

3 0

3 years ago

Hey guys plz help with this one i beg

kvv77 [185]

Answer:

102

Step-by-step explanation:

i think it is the ans.

6 0

3 years ago