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3 years ago

Please help me ASAP!!!!

Mathematics

1 answer:

egoroff_w [7]3 years ago

3 0

Answer:

x intercept =

$- \frac{5}{3} and \: y \: intercept \: = \: \frac{5}{4}$

Step-by-step explanation:

i show how i did it on the picture! :)

and for future reference, if you need to figure out the y-intercept, just do what i did but except cover up the x! :)

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Jesse collects data on his math scores on the last 12 tests and the number of hours he spent completing his math homework

oksian1 [2.3K]

Answer:14

Step-by-step explanation:7+7=14

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3 years ago

Which condition must be satisfied in order to use the arc length formula L = the integral from a to b of sqrt(1 + f'(x)^2) dx?

ivanzaharov [21]

Looking through my old calc notes, I am reading that f(x) needs to be continuous on [a,b] and f ' (x) also needs to be continuous on [a,b]. Both conditions are needed. If you had to pick just one, then I'd say f(x) being continuous is much more important. Though I'm not 100% sure on this one. My thinking is that if there was any discontinuities on f(x), then the arc length would be distorted and overblown. The arc length should not account for any piece that isn't on the curve.

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3 years ago

Hunter is playing a video game where each round lasts ¾ of an hour. He has scheduled 3 hours to play video games. How many round

NemiM [27]

Answer:

45×4=180

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3 0

3 years ago

Flip a coin 10 times and record the observed number of heads and tails. For example, with 10 flips one might get 6 heads and 4 t

zepelin [54]

Answer:

The greater the sample size the better is the estimation. A large sample leads to a more accurate result.

Step-by-step explanation:

Consider the table representing the number of heads and tails for all the number of tosses:

Number of tosses n (HEADS) n (TAILS) Ratio

10 3 7 3 : 7

30 14 16 7 : 8

100 60 40 3 : 2

Compute probability of heads for the tosses as follows:

n = 10 tosses

$P(\text{HEADS})=\frac{3}{10}=0.30$

The probability of heads in case of 10 tosses of a coin is -0.20 away from 50/50.

n = 30 tosses

$P(\text{HEADS})=\frac{14}{30}=0.467$

The probability of heads in case of 30 tosses of a coin is -0.033 away from 50/50.

n = 100 tosses

$P(\text{HEADS})=\frac{60}{100}=0.60$

The probability of heads in case of 100 tosses of a coin is 0.10 away from 50/50.

As it can be seen from the above explanation, that as the sample size is increasing the distance between the expected and observed proportion is decreasing.

This happens because, the greater the sample size the better is the estimation. A large sample leads to a more accurate result.

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3 years ago

Your friend claims that there is not enough information given to find the value of x.Is your friend correct?

Kay [80]

No not a full question

6 0

4 years ago