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natima [27]
3 years ago
8

Please help me ASAP!!!!

Mathematics
1 answer:
egoroff_w [7]3 years ago
3 0

Answer:

x intercept =

-  \frac{5}{3}  and \: y \: intercept \:  =  \:   \frac{5}{4}

Step-by-step explanation:

i show how i did it on the picture! :)

and for future reference, if you need to figure out the y-intercept, just do what i did but except cover up the x! :)

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Find the length of the line segment that connects the points (7, 16) and (47, 140)​
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length =  \sqrt{ {(47 - 7)}^{2}  +  {(140 - 16)}^{2} }  \\  =  \sqrt{ {40}^{2}  +  {124}^{2} }  \\  =  \sqrt{16976}  \\  = 130.29 \: units

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3 years ago
Which statements are true about the locations of points A and B? Select all that apply. O Point A is at (0, -2). Point A is at (
elena-s [515]
The answer is "Point B is at (-8, -7)". let's remember that -8 represents the x-axis, and -7 represents the y-axis.
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3 0
3 years ago
A long jumper lifts off 3 m after starting his run, and lands 6 m later. When he is 8 m from the start line, he is 5 cm above an
slega [8]

Answer:

The equation of the parabola that models the path of the long jumper through the air is y = -x^{2}+12\cdot x -27.

Step-by-step explanation:

Mathematically, we know that parabolas are second-order polynomials and every second-order polynomials, also known as quadratic functions, can be constructed by knowing three different points of the curve. The standard form of the parabola is:

y = a\cdot x^{2}+b\cdot x + c

Where:

x - Horizontal distance from the start line, measured in meters.

y - Height of the long jumper, measured in meters.

a, b, c - Polynomial constants, measured in \frac{1}{m}, dimensionless and meters, respectively.

If we know that (x_{1},y_{1}) = (3\,m, 0\,m), (x_{2},y_{2}) = (8\,m, 0.05\,m) and (x_{3}, y_{3}) = (9\,m, 0\,m), this system of linear equations is presented below:

9\cdot a + 3\cdot b + c = 0 (Eq. 1)

81\cdot a + 9\cdot b + c = 0 (Eq. 2)

64\cdot a + 8\cdot b + c = 0.05 (Eq. 3)

The coefficients of the polynomial are, respectively:

a = -\frac{1}{100}, b = \frac{3}{25}, c = -\frac{27}{100}

The equation of the parabola that models the path of the long jumper through the air is y' = -\frac{1}{100}\cdot x^{2}+\frac{3}{25}\cdot x -\frac{27}{100}.

But we need y measured in centimeters, then, we use the following conversion:

y = 100\cdot y'

Then, we get that:

y = -x^{2}+12\cdot x -27

Where x and y are measured in meters and centimeters, respectively.

The equation of the parabola that models the path of the long jumper through the air is y = -x^{2}+12\cdot x -27.

4 0
3 years ago
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