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dangina [55]
3 years ago
7

8+0=8 describe the number sentence

Mathematics
2 answers:
Wittaler [7]3 years ago
8 0
Whatever is adding with 0 its that number its like mulitipulcation with 1 because whatever is times by one like 25x1= 25
DanielleElmas [232]3 years ago
5 0
First you add 0 to to eight and there is your awnser  √√√√√√
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A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea
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Answer:

The least cost of fencing for the rancher is $1200

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Let <em>x</em> be the width and <em>y </em>the length of the rectangular field.

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C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}

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20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30

Because the length is always positive the only point we take is x=30. We thus test the intervals (0, 30) and (30, \infty)

C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0

we see that total cost function is decreasing on (0, 30) and increasing on (30, \infty). Therefore, the minimum is attained at x=30, so the minimal cost is

C(30)=20(30)+\frac{18000}{30}\\C(30)=1200

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Here’s the diagram:

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Step-by-step explanation:

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