All categories

3 years ago

Write an expression for the sequence of operations described below.

Mathematics

1 answer:

IgorC [24]3 years ago

5 0

The answer to this would be the following:
9 + 7 x 9

You might be interested in

I really need help with this trigonometric function, i am struggling and it would mean a lot.

AURORKA [14]

Answer:

should be 22.5 for the first one and 324 for the second

Step-by-step explanation:

pi = 180° so you can take the multiplier by pi and switch pi to be 180

7 0

3 years ago

What is an equivalent expression to<br> 4-(-5)

mrs_skeptik [129]

Answer:

Step-by-step explanation:

Well you will need to simplify -(-5)

So you need to multiply - by -5

negative times negative is positive so the answer for that is 5

so the equation looks like this: 4+5

4+5 is 9

Answer:9

Hope this helps!

5 0

3 years ago

Read 2 more answers

I don't get it please help

Elis [28]

2, (double) 4, (double) 8 (double) 16, So 16 in week 4
2+4+8+16 = 30

5 0

3 years ago

Read 2 more answers

Please help answer all please thank you

mr Goodwill [35]

Answer:

The answers are, in order:

1. Isolate

2. substitute

3. variable

Step-by-step explanation:

You're welcome :)

5 0

3 years ago

A man claims to have extrasensory perception (ESP). As a test, a fair coin is flipped 20 times, and the man is asked to predict

dlinn [17]

Answer:

$P(x\geq 17)=0.00128$

Step-by-step explanation:

The probability that the man gets x out of 20 correct follows a Binomial distribution, so the probability is calculated as:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}$

Where n is the number of identical experiments and p is the probability of success. In this case n is 20.

Additionally, if he has no ESP the probability that he predict correctly is 0.5, because he is only guessing.

Then, the probability that he gets x out of 20 correct is equal to:

$P(x)=\frac{20!}{x!(20-x)!}*0.5^{x}*(1-0.5)^{20-x}$

Therefore the probability that he would have done at least 17 out of 20 well if he had no ESP is:

$P(x\geq 17)=P(17)+P(18)+P(19)+P(20)\\$

Where:

$P(17)=\frac{20!}{17!(20-17)!}*0.5^{17}*(1-0.5)^{20-17}=0.00108719\\P(18)=\frac{20!}{18!(20-18)!}*0.5^{18}*(1-0.5)^{20-18}=0.00018119\\P(19)=\frac{20!}{19!(20-19)!}*0.5^{19}*(1-0.5)^{20-19}=0.00001907\\P(20)=\frac{20!}{20!(20-20)!}*0.5^{20}*(1-0.5)^{20-20}=0.00000095$

So, $P(x\geq 17)$ is equal to:

$P(x\geq 17)=0.00108719+0.00018119+0.00001907+0.00000095\\P(x\geq 17)=0.00128$

8 0

3 years ago