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maw [93]
3 years ago
12

Find the RANGE for the data set: 8, 4, 6, 6, 8, 2, 6,5

Mathematics
2 answers:
saul85 [17]3 years ago
6 0

Answer:

\boxed {\boxed {\sf range= 6}}

Step-by-step explanation:

The range of a data set is the difference between the biggest value and the smallest value.

We are given this data set:

  • 8, 4, 6, 6, 8, 2, 6, 5

If we order it from smallest to largest:

  • 2, 4, 5, 6, 6, 6, 8, 8

We see that the smallest value is 2 and the largest is 8. Now we can find the range.

  • range= largest value - smallest value
  • range= 8-2
  • range= 6

The range for the data set is <u>6.</u>

Ber [7]3 years ago
3 0
Range = highest number - lowest number
Highest number = 8
Lowest number = 2
Range = 8-2 = 6

6 is the range
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3 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
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