Ribbon cost $1.44 for 3 m what is the cost per metre?

The scale on a map is 1/4 inch equals 3/4 mile. How long is one mile on the map?

frozen [14]

Answer:it would be 1/16+1/4=1 mile

Step-by-step explanation:

3 0

4 years ago

A thin layer of paint is 7x10^-7 m thick. In contrast, a coin is 3.43 x 10^-3 m thick. How many layers of paint are in a stack

faltersainse [42]

There's 4 layers of paint cause you should just add 4 to 3.43 and you get 7.43 x 10^-7..?

7 0

3 years ago

please i need the answers asap can you explain it to please...suzanne is organizing a disco how much should she charge for each

Semmy [17]

Wouldnt u add all those amounts of money then divide it by 40 so it would give u the amount of money needed to cover her costs?

3 0

3 years ago

The region in the first quadrant bounded by the x-axis, the line x = In(pi), and the curve y = sin(ex) is rotated about the x-ax

Basile [38]

Answer:

D

Step-by-step explanation:

Please refer to the graph below.

So, we want to find the volume of the solid generated by revolving the green area about the x-axis.

We can use the disk method. The disk method is given by:

$\displaystyle V=\pi\int_a^bR(x)^2\, dx$

Where R(x) is the radius or height of the representative rectangle.

We are integrating from x = 0 to x = ln(π). The height of a representative rectangle is given by y. Therefore, the volume is:

$\displaystyle V=\pi\int_0^{\ln(\pi)}(\sin(e^x))^2\, dx$

Simplify:

$\displaystyle V=\pi\int_0^{\ln(\pi)}\sin^2(e^x)\, dx$

Approximate. So, the volume of the generated solid is:

$V\approx 2.498\text{ units}^3$

The solid is shown in the second figure.

(Courtesy of WolframAlpha.)

7 0

3 years ago

The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va

Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

$d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore$

4 0

4 years ago