Answer:
There are 47 Borogroves and 35 Mome raths
Step-by-step explanation:
Here, given the number of legs, we want to find the number of each type of animals
Let the number of borogoves be b and the number of mome raths be m
From the question, there are 82 creatures;
Thus;
m + b = 82 ••••••••(i)
the total number of legs by b borogroves will be b * 2 = 2b
the total number of legs by m mome raths will be m * 4 = 4m
the sum of all legs is 234
2b + 4m = 234 •••••••••(ii)
From equation 1, m = 82-b
Substitute this into equation ii
2b + 4(82-b) = 234
2b + 328 - 4b = 234
4b-2b = 328-234
2b = 94
b = 94/2
b = 47
Recall;
m + b = 82
m + 47 = 82
m = 82-47
m = 35
X^2 - 14 x = 15
(x - 7)^2 - 49 = 15
(x-7)^2 = 64
x - 7 = - or + 8
x = 15 or -1
Just take half o the coefficient of x and subtract it squared as above.
In general
x^2 + ax = b
(x + a/2)^2 - a^2/4 = b
Well 1 divided by 5 is .2 so when you take that in consideration, you can place them in easier so 2*5 is 10 and add one so 11 1/5 cups <span />
Answer:
the answer is $60
Step-by-step explanation:
5x12=60
