All categories

2 years ago

Compare mâˆ 1 and mâˆ 2. what theorem are you using when you compare the angles in the two triangles?

1 answer:

6 0

SAS and SSS Inequality Theorems. Look at the triangle below. The sides of the triangle are given.

You might be interested in

If JK = 7, KH = 21, and JL = 6, find LI, x and TV.

Natali [406]

As per given:

$\begin{gathered} \frac{JK}{KH}=\frac{JL}{LI} \\ \frac{7}{21}=\frac{6}{LI} \\ LI=\frac{21\times6}{7} \\ LI=3\times6 \\ LI=18 \end{gathered}$

6 0

1 year ago

Translate the expression with rational exponents into a radical expression. Simplify if necessary.

mars1129 [50]

Look at the attached picture⤴

Hope it will help u..

6 0

3 years ago

Read 2 more answers

Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. N an 1 4 2 −12 3 36 t

Rzqust [24]

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is $\sum_{n=4}^{15} 5(-2)^{n-1}$$$

<h3>What is sequence ?</h3>

Sequence is collection of numbers with some pattern .

Given sequence

$a_{1}=5\\\\a_{2}=-10\\\\\\a_{3}=20$

We can see that

$\frac{a_1}{a_2}=\frac{-10}{5}=-2\\$

and

$\frac{a_2}{a_3}=\frac{20}{-10}=-2\\$

Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2

Now $n^{th}$ term of this Geometric progression can be written as

$T_{n}= 5\times(-2)^{n-1}$

So summation of 15 terms can be written as

$\sum_{n=4}^{15} T_{n}\\\\$\\$\sum_{n=4}^{15} 5(-2)^{n-1}$$$

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is $\sum_{n=4}^{15} 5(-2)^{n-1}$$$

To learn more about Geometric progression visit : brainly.com/question/14320920

8 0

2 years ago

I need help ASAP (20points)

Leto [7]

y = x^2 + 2x...eqn 1

y = 3x + 20...eqn 2

subst for y in eqn 1...

=> x^2 +2x = 3x +20

=> x^2 - x - 20 =0

=> (x-5) (x+4) =0

=> x = 5 or -4

for x =5, y = 35 (sub for x in eqn 1 or 2)

for x = -4, y = 8 (sub for x in eqn 1 or 2)

5 0

3 years ago

The post office will accept packages whose combined length and girth is at most 42 inches. (the girth is the perimeter/distance

Vilka [71]

If x represents the length of the box, then 42-x will be the girth. Since the largest area for a given girth is that of a square, the side length of the square cross section is (42 -x)/4.

The volume as a function of package length is then
.. v(x) = x((42-x)/4)^2
This has a maximum at x=14. The corresponding volume is 686 in^3.

8 0

3 years ago