Answer:
x = 0
, y = 4
Step-by-step explanation:
Solve the following system:
{y = 4 - 3 x | (equation 1)
x + 2 y = 8 | (equation 2)
Express the system in standard form:
{3 x + y = 4 | (equation 1)
x + 2 y = 8 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 x + y = 4 | (equation 1)
0 x+(5 y)/3 = 20/3 | (equation 2)
Multiply equation 2 by 3/5:
{3 x + y = 4 | (equation 1)
0 x+y = 4 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = 0 | (equation 1)
0 x+y = 4 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 0 | (equation 1)
0 x+y = 4 | (equation 2)
Collect results:
Answer: {x = 0
, y = 4
First, we simplify this to 3/4-j/12=0. 4/4=1 so we do, -j=-51/4*-1. Therefore, the answer is j=51/4. Hoped I helped. :)
I think the answer is <1=34
Assuming that the artist wants to paint 6 sides of the cube, the formula to count the surface area of the cube would be: 6* edge length^2. If the edge length is 10 feet, then the area would be:
area= 6*edge length^2
area= 6* 10^2 feet
area= 6*100feet^2= 600 feet^2
If one gallon of paint can be used for 350 feet^2, the amount of paint needed would be: 600feet^2/ (350ft^2/ gallon)= 1.71 gallon
Answer:
First piece = 6 inches
Second piece = 12 inches
Third piece = 18 inches
Step-by-step explanation:
Length of the first piece = x
Length of the second piece = 2x
Length of the third piece = 3x
Total length is 36 inches:
x + 2x + 3x = 36
6x = 36
x = 6
Therefore, the lengths are:
First piece = 6 inches
Second piece = 12 inches
Third piece = 18 inches
