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Stolb23 [73]
3 years ago
6

Helen is an engineer that designs packages for new products she designed a box in the shape of a rectangle Prism with dimensions

of 10 by 7 Inches by 4 inches what is the surface area of the box
Mathematics
2 answers:
VARVARA [1.3K]3 years ago
7 0

7×4=28×2=56

7×10=70×2=140

4×10=40×2=80

56+140+80=376cm

USPshnik [31]3 years ago
3 0

Answer: it is 276

if i can be brainliest that would be great

10x7= 70 (Base 1)

10x7= 70 (Base 2)

10x4= 40 (Front)

10x4= 40 (Back)

 7x4= 28 (Side 1)

 7x4= 28 (Side 2)

---------------------------------

  SA= 276

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Answer pls thank you
Luba_88 [7]

Step-by-step explanation:

l

  1. lcm 3
  2. use the lcm to divide the answers by 3

7 0
3 years ago
The perimeter of a rectangular field is 328 yards. If the length of the field is 89 yards, what is its width?
miv72 [106K]

<u>Set up an equation based on the information given</u>

89 + 89 + x + x = 328

<u>Combine like terms</u>

89 + 89 = 178

x + x = 2x

2x + 178 = 328

<u>Solve</u>

2x + 178 = 328

328 - 178 = 150

2x = 150

x = 75

Answer

The width of the rectangular field is 75 yards.

7 0
3 years ago
A polynomial that can be factored is called
Bingel [31]
<span>reducible.

hope this helps</span>
4 0
3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
Determine the approximate value of x.
nordsb [41]

Answer:

 C.    6.736

Step-by-step explanation:

I took the test and got a 100%.

8 0
3 years ago
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