<h3>
Answer: f(x) = (-1/2)x+1, choice B</h3>
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Explanation:
The diagonal line passes through 1 on the vertical y axis. So the y intercept is b = 1. This means the location of the y intercept is (0,1).
Start at (0,1) and move down 1 and to the right 2 to arrive at (2,0). This is another point on the diagonal line. The motion of "down 1 and right 2" is effectively the slope
slope = rise/run = -1/2
rise = -1, run = 2
The rise being negative means we have gone downhill as we move to the right.
With m = -1/2 as the slope and b = 1 as the y intercept, we go from y = mx+b to y = (-1/2)x+1
The last thing to do is replace y with f(x) to get f(x) = (-1/2)x+1 as the final answer.
Answer:
The sales level that has only a 3% chance of being exceeded next year is $3.67 million.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
In millions of dollars,

Determine the sales level that has only a 3% chance of being exceeded next year.
This is the 100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So X when Z = 1.88.




The sales level that has only a 3% chance of being exceeded next year is $3.67 million.
It’s y=3x-3 that is where the line passes thru
7. the formula for octagon is a=2(1+radical2)s^2
s=4
a=about 77.25
8.
Answer:
P = 0.332
Step-by-step explanation:
The probability of having the disease is 0.08
The probability that the test predicts with accuracy is 0.7.
We need to find the probability that the test positive for the disease.
Several cases may occur.
Case 1.
You have the disease and the test predicts it accurately

Case 2
You do not have the disease and the test predicts that you have it

Then the probability that the test predicts that you have the disease is the union of both probabilities P1 and P2
