3 years ago

Evaluate C(5, 2). 10 20 30

Mathematics

1 answer:

JulsSmile [24]3 years ago

8 0

Answer:

Step-by-step explanation:

$C(5,2)=\frac{5*4}{2*1} =10$

You might be interested in

EASY WORK!! Plz look at the photo and yes it’s easy for other people but not me .

Svetach [21]

Answer: 48

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

?????????????????????????????))???

Gnom [1K]

HI THERE!!!

The answer you chose is correct: Face

Have great Saturday!!!!!!!!

~TRUE BOSS

3 0

2 years ago

What is the slope for this graph?* (3,2) |(1,2) (-2,1) (-1,2)

Ad libitum [116K]

Answer:

the slope is 0

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Please answer this question! 30 points and brainliest!

Darya [45]

That you and her have a 50% chance of winning.

3 0

3 years ago

Lim x approaches 0 (1+2x)3/sinx

jok3333 [9.3K]

Interpreting your expression as

$\dfrac{3(1+2x)}{\sin(x)}$

when $x$ approaches zero, the numerator approaches 3:

$3(1+2x) \to 3(1+2\cdot 0) = 3(1+0) = 3\cdot 1 = 3$

The denominator approaches 0, because $\sin(0)=0$

Moreover, we have

$\displaystyle \lim_{x\to 0^-} \sin(x) = 0^-,\quad \displaystyle \lim_{x\to 0^+} \sin(x) = 0^+$

So, the limit does not exist, because left and right limits are different:

$\displaystyle \lim_{x\to 0^-} \dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^-} = -\infty,\quad \displaystyle \lim_{x\to 0^+}\dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^+} = +\infty$

8 0

2 years ago