Answer with explanation:
Average Height of tallest Building in San Francisco
Average Height of tallest Building in Los Angeles
→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco
=233.9-197.8
=36.1
⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.
⇒Part B
Mean absolute deviation for the 10 tallest buildings in San Francisco
|260-197.8|=62.2
|237-197.8|=39.2
|212-197.8|=14.2
|197 -197.8|= 0.8
|184 -197.8|=13.8
|183-197.8|=14.8
|183-197.8|= 14.8
|175-197.8|=22.8
|174-197.8|=23.8
|173 -197.8|=24.8
Average of these numbers
Mean absolute deviation=23.12
The question asks for the rate of toys per hour.
So we shall divide the total toys assembled by the total hours.
Its a five day week.
The number of hours allotted per day are 8.
So total allotted during the week are 8 × 5 = 40 hours.
Number of toys made during the week are 400.
Hence the number of toys assembled per hour per person
= number of toys / number of hours
= 400 / 40
= 10 toys per hour per person.
The average number of toys assembled per hour per person is 10.
I don't know the second on but the first is pint
There should be 1,400 pages in an order that costs the same for both companies.
Let x be the unknown number of pages.
1st Company = 42 + 0.05x
2nd Company = 0.08x
0.08x = 42 + 0.05x
0.08x - 0.05x = 42
0.03x = 42
0.03x / 0.03 = 42 / 0.03
x = 1400 pages
To check
0.08x = 42 + 0.05x
0.08 (1400) = 42 + (0.05 * 1400)
112 = 42 + 70
112 = 112
