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Zinaida [17]
2 years ago
13

Find the GCF of each set of numbers 150, 200, and 300

Mathematics
1 answer:
jolli1 [7]2 years ago
3 0
Your GCF is 50 of each set of numbers
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5. It is known that AABC = ADEF. If AB = 5, BC = 10, AC = 8, and DF = 2x-6, then solve for the value of
lorasvet [3.4K]

Answer:

The value of x is 7

Step-by-step explanation:

we know that

If two figures are congruent, then the corresponding angles and the corresponding sides are equal

In this problem

Triangles ABC and DEF are congruent

ABC≅DEF

therefore

AB=DE ----> equation A

AC=DF ----> equation B

BC=EF ----> equation C

Substitute the given values in the equation B

8=2x-6

Solve for x

2x=8+6

2x=14

x=7

therefore

The value of x is 7

The draw in the attached figure

3 0
3 years ago
At a bake sale there were 90 items sold total. If 42 of the items sold were cookies and the rest were brownies what is the ratio
kari74 [83]
Firstly, you do 90 - 42 to get the amount of brownies sold, which is 48. Then, you put 42 and 48 into a ratio like 42:48. After that, all you need to do is simplify to get 7:8.
5 0
3 years ago
If (-1, y) lies on the graph of y= 2^2x, then y=<br> -4<br> 1/4<br> 1
AfilCa [17]

Answer:

1/4

Step-by-step explanation:

Substitute x=-1 to find y

Given y= 2^2x

y(-1)=2^-2=1/(2^2)

7 0
2 years ago
A vehicle arriving at an intersection can turn right, turn left, or continue straight ahead. The experiment consists of observin
Temka [501]

Answer:

a) Sample space (S) = {TR, TL, Cs}

b) Pr(Vehicle Turns) = 2/3.

Step-by-step explanation:

a) By sample space (S) we mean the list all possible outcome of an event. From the illustration in the question, only three (3) outcome is possible:

i) Vehicle Turn Right (TR)

ii) Vehicle Turn Left (TL)

iii) Continue Straight ahead (Cs)

And since the experiment consists of observing the movement of a single vehicle through the intersection, then, the sample space (S) is:

==> {TR, TL, Cs}

b) Since we are assuming that all sample points are equally likely, it imply that they have equal probability of occurring. And by probability:

Pr(TR) = 1/3

Pr(TL) = 1/3

Pr(Cs) = 1/3

Meanwhile, the question wants us to find the probability that the vehicle turns. This means, the vehicle turning either right or left. Thus;

Pr(vehicle turns) = Pr(TR) or Pr(TL) = Pr(TR) + Pr(TL)

Pr(vehicle turns) = (1/3) + (1/3) = 2/3

4 0
3 years ago
Need help please!<br> Asap!
docker41 [41]

Answer:

deese nots

Step-by-step explanation:

5 0
2 years ago
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