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liq [111]
3 years ago
8

HELP PLSSSSSS (-2) X (3 4/7) Distributive property????

Mathematics
1 answer:
sweet [91]3 years ago
4 0
-68/7 or -9.714286


hope this helped ✨!
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Artyom0805 [142]

Answer:

22.5 batches

Step-by-step explanation:

6 0
3 years ago
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Gia got some books from Library yesterday she got five books today Gia returned three books Gia has six books how many books did
makvit [3.9K]

Answer: 4


Explanation:


You can write an algebraic expression to represent the sequence with the books in this way:

  • yesterday she got five books: 5
  • today returned three books: - 3
  • how many books did Gia have to begin: n
  • At the end she has six books, which means that you can set an equality:

       n + 5 - 3 = 6

Now you follow these steps to clear the unknown:

  • do the operations in the left side: n + 2 = 6
  • use subtraction property of equality: n = 6 - 2
  • do the operations: n = 4

And that is the number of books whith which Gina started: 4

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3 years ago
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morpeh [17]

Answer:

A

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u move the decimal place left 2 spaces and u would get 0.024

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2 years ago
What methods of charging does John use?
lidiya [134]

Answer: The rod through induction electroscope through friction

Step-by-step explanation:

8 0
3 years ago
The probability that a rental car will be stolen is. 4. if 3500 cars are rented, what is the approximate poisson probability tha
kozerog [31]

Using the Poisson distribution, there is a 0.8335 = 83.35% probability that 2 or fewer will be stolen.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

The probability that a rental car will be stolen is 0.0004, hence, for 3500 cars, the mean is:

\mu = 3500 \times 0.0004 = 1.4

The probability that 2 or fewer cars will be stolen is:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-1.4}1.4^{0}}{(0)!} = 0.2466

P(X = 1) = \frac{e^{-1.4}1.4^{1}}{(1)!} = 0.3452

P(X = 2) = \frac{e^{-1.4}1.4^{2}}{(2)!} = 0.2417

Then:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2466 + 0.3452 + 0.2417 = 0.8335

0.8335 = 83.35% probability that 2 or fewer will be stolen.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

4 0
1 year ago
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