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fiasKO [112]
3 years ago
12

Which of these values would you most likely see on a U.S. speed limit sign?

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
7 0

Answer:

A. 55 miles/hour

Step-by-step explanation:

vovangra [49]3 years ago
7 0

Answer:

A. 55 Miles/hour

Step-by-step explanation:

The other ones just don't make sense. You'd never see the other ones on a U.S speed sign

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Help me please ASAP ......
Dvinal [7]
4. 3(y + 4y) this is distributive property!  Hope it helps. Btw can you please check out a question on my page? thanks!! <span />
5 0
3 years ago
1/x^-2 x=7 yeet yeet
Yanka [14]

Answer:

49

Step-by-step explanation:

x = 7

1 / x^-2

= x^2

= 7^2

= 49

8 0
2 years ago
Casey said that 0.03*1,000 is 3 explain why caseys answer is wrong what mistake do u think he made
Igoryamba
<span>0.03 x 1,000=30! In multiplying decimals, you'll move the decimal's period to the number of zeroes in the multiplier! 1,000 has 3 zeroes. So, it's equal to 30. So basically he was wrong because 0.03 times 1,000 doesn't equal 3 it equals 30. He made the mistake of not moving the decimal point enough.</span>
6 0
3 years ago
2. Margie Spencer wants to have $100,000 in her savings account in 20 years. If her account pays 6.6% annual
WITCHER [35]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$100000\\ P=\textit{original amount deposited}\\ r=rate\to 6.6\%\to \frac{6.6}{100}\dotfill &0.066\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus two} \end{array}\dotfill &2\\ t=years\dotfill &20 \end{cases}

100000=P\left(1+\frac{0.066}{2}\right)^{2\cdot 20}\implies 100000=P(1.033)^{40} \\\\\\ \cfrac{100000}{1.033^{40}}=P\implies 27288.97\approx P

7 0
2 years ago
Find the distance between the two points rounding to the nearest tenth (if needed)
Ede4ka [16]

Answer:

6.3 units (nearest tenth)

Step-by-step explanation:

\boxed{Distance \: between \: 2 \: points =  \sqrt{ {(x1 - x2)}^{2} +  {(y1 - y2)}^{2}  } }

Using the formula above,

distance between (-8, 6) and (-6, 0)

=  \sqrt{ {[ - 8 - ( - 6)]}^{2}  +  {(6 - 0)}^{2} }

=  \sqrt{ {( - 8 + 6)}^{2}  +  {(6 - 0)}^{2} }

=  \sqrt{ {( - 2)}^{2} + 6^{2}  }

=  \sqrt{4 + 36}

=  \sqrt{40}

= 6.3 units (nearest tenth)

3 0
2 years ago
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