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mr Goodwill [35]
3 years ago
13

A woman who is 5 feet 5 inches tall is standing near the Space Needle in Seattle, Washington. She casts a 13-inch shadow at the

same time that the Space Needle casts a 121-foot shadow. How tall is the Space Needle?
Mathematics
1 answer:
geniusboy [140]3 years ago
7 0
Converting to inches we have
\\  \frac{65}{13} =  \frac{x}{121 \times 12} \: or \\  \frac{65}{13} =  \frac{x}{1452} \: so \\ (65)(1452) = 13x \: so \\ x =  \frac{(65)(1452)}{13} = 7260 \: inches \\  =  \frac{7260}{12} = 65feet \\ as \: the \: height \: of \: the \: space \: needle
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a

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Andreas93 [3]

Answer:

0.192 - 1.645\sqrt{\frac{0.192(1-0.192)}{250}}=0.151

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Information given

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In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

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0.192 - 1.645\sqrt{\frac{0.192(1-0.192)}{250}}=0.151

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