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mr Goodwill [35]
2 years ago
13

A woman who is 5 feet 5 inches tall is standing near the Space Needle in Seattle, Washington. She casts a 13-inch shadow at the

same time that the Space Needle casts a 121-foot shadow. How tall is the Space Needle?
Mathematics
1 answer:
geniusboy [140]2 years ago
7 0
Converting to inches we have
\\  \frac{65}{13} =  \frac{x}{121 \times 12} \: or \\  \frac{65}{13} =  \frac{x}{1452} \: so \\ (65)(1452) = 13x \: so \\ x =  \frac{(65)(1452)}{13} = 7260 \: inches \\  =  \frac{7260}{12} = 65feet \\ as \: the \: height \: of \: the \: space \: needle
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How to understand piecewise functions
Nataly [62]
Each piece is defined over some (limited) domain. When you are evaluating or graphing a piecewise function, you only evaluate or graph the function whose domain includes the variable value of interest.
6 0
3 years ago
In the problem, 2x4 - 3x3 - 6x2 + 11x +8 divided by (x - 2), what is the remainder?
Jet001 [13]

remainder = 14

2x^{4} - 3x^{3} - 6x² + 11x + 8

= 2x³ + x² - 4x + 3 + \frac{14}{x - 2}


8 0
3 years ago
The sum of two consecutive integers is -95. Find the integers. State the unknov-
kvasek [131]

Let the unknown consecutive integers be x, x+1

x+x+1=-95

2x+1=-95

2x=-95-1

2x=-96

x=-96/2

x=-48

x=-48

x=-48x+1=-48+1=-47

-48 and -47 are the two consecutive integers

Please mark as Brainliest

8 0
2 years ago
A baseball is thrown into the air from the top of a 224-foot tall building. The baseball's approximate height over time can be r
antoniya [11.8K]
The function is h(t) = -16t^2 + 80t + 224, and according to the description of the function in the problem statement, we have the following:

at t=0 after being thrown (that is, at initial time), the height of the ball is calculated by h(0) as follows:

h(0) = -16(0)^2 + 80(0) + 224=0+0+224=224 (ft), which is the initial height, as expected.


At t=1 (sec), the height would be  h(1) = -16(1)^2 + 80(1) + 224=-16+80+224=288. 

etc.


The path is parabolic, as we know by seeing that the function is a quadratic polynomial function. This function has been given in factored form as well. From that we can see that the zeros of the function are t=7 and t=-2.

This means that at t=7 sec, the height h is 0, which means that the ball has hit the ground. t=-2 has no significance in the context of our problem so we just neglect it.


Answer: B) 7 sec



6 0
3 years ago
Read 2 more answers
For some postive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770. The value of Z is
Talja [164]

Answer:

1.16

Step-by-step explanation:

Given that;

For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.

This implies that:

P(0<Z<z) = 0.3770

P(Z < z)-P(Z < 0) = 0.3770

P(Z < z) = 0.3770 + P(Z < 0)

From the standard normal tables , P(Z < 0)  =0.5

P(Z < z) = 0.3770 + 0.5

P(Z < z) =  0.877

SO to determine the value of z for which it is equal to 0.877, we look at the

table of standard normal distribution and locate the probability value of 0.8770. we advance to the  left until the first column is reached, we see that the value was 1.1.  similarly, we did the same in the  upward direction until the top row is reached, the value was 0.06.  The intersection of the row and column values gives the area to the two tail of z.   (i.e 1.1 + 0.06 =1.16)

therefore, P(Z ≤ 1.16 ) = 0.877

8 0
3 years ago
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