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3 years ago

5

The stem-and-leaf plot. represents the number of flowers in different public gardens throughout the city. How many gardens have

at least 18 flowers, but fewer than 30 flowers.
Enter your answer in the box

1 5667788
2 1459
3 0056

1 answer:

zlopas [31]3 years ago

4 0

There are 6 numbers that are greater than or equal to 18 and less than 30.

6 gardens have 18-29 flowers.

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When I double my number, add four, and then subtract my number and subtract three, I get my number plus one. What is my number?

Helen [10]

The number is 2 because 4_

3=1 and 1+1=2

8 0

2 years ago

Calculate the mass of a rectangular solid that has a density of 2.53 g/cm3 and which measures 25 mm by 1.80 cm by 3.00 cm.

Annette [7]

Mass = density x volume
1st we need to get the volume
V = (25*10^-1) * (1.8) * (3)
V = 13.5 cm3
mass = 2.53 * 13.5
mass = 34.155 kg

3 0

2 years ago

Is negative 108.8 rational?

lord [1]

The number -108.8 is a rational number

<h3>How to determine if the number is rational?</h3>

The number is given as:

negative 108.8

Rewrite properly as:

-108.8

Rational number have terminating decimals, and they can be represented as fractions.

The fraction equivalent of -108.8 is -1088/10

Hence, the number -108.8 is a rational number

Read more about rational numbers at:

brainly.com/question/1535013

#SPJ1

8 0

1 year ago

A tire company produced a batch of 6 comma 700 tires that includes exactly 250 that are defective.

mezya [45]

the probability that if you pick only one, it's defective, is 250/6700

Therefore, the probability that one is not defective is 6450/6700

a. You want all 4 to not be defective: (6450/6700)^4

b. all 100 have to be not defective: (6450/6700)^100

If you type this into a calculator, you will get about 0.022, so a probability of 2 % that all of them are not defective. As this is a very small probability, the outlet should plan with returned tires.

8 0

2 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

4 0

2 years ago