Given:
Morgan = 500 meters from her house
Length of leash = 8 meters
minimum distance of the dog from the house 500 - 8 = 492 meters.
maximum distance of the dog from the house 500 + 8 = 508 meters.
Answer:
y = -x/6 + 2
Step-by-step explanation:
A is the minimum value
B is the first quartile
The point with the line through it (next to C) is the median.
The point to the outside of the box is the third quartile.
D is the maximum value.
Hope this helped.
Answer:
![r=\sqrt[3]{\frac{3V}{4\pi}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D)
Step-by-step explanation:
We need to isolate 'r'
To isolate 'r' , first multiply by 3 on both sides
divide by 4pi on both sides
Take cube root on both sides
![\sqrt[3]{\frac{3V}{4\pi}}= r](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%7D%7D%3D%20r)
