There will be one solution. To solve that:
1. Get the y alone by switching the places.
6x+y=2 > y=2-6x
-18x+3y=12 > 3y=12-18x > Then divide 3 on each number > y=4-6x
After doing that, you can solve this in graphing or algebra way.
Ima do the algebra way:
SO we have 2 system of equations. Now pick one equestion.
I will pick, y=2-6x. Now Ima replace the Y with the other equation y=4-6x >
4-6x=2-6x.
Now solve. And get > 0 aka Infinite Solution.
I might be wrong but you tell me,
The father is 60 years old.
Son lives to be 60.
Total is 120.
Both die at the age of 60.
Could the son have been a newborn?
Idk. I don't understand it.
Wait, sum of present ages is 60. The son has to be younger by at least 20. Double it again. No, even then newborn is 0 and then 60= 60. Son lives toll he's 60 and dies, 120. Sorry, I tried. What are your possible choices?
Differentiate with respect to x and y
2x +10 y y' = 0
get y' alone
y' = -2x/(10 y)
reduce
y'=-x/(5y)
continue with quotient rule of differentiation
y'' = ( 5y(-1) - (-x) (5y')) / (5y) squared
y'' = (-5y + 5xy') / (25y squared)
reduce by dividing each term by 5
y" = (-y +xy') / (5y squared) answer
Now if the teacher wants you to continue so no y or y' shows
substitute y' = -x/(5y) and y = square root ((5-x squared) / 5)
and simplify
Answer:
The probability that all are shipped on time is 0.729
Step-by-step explanation:
Consider the provided information,
It is given that the probability that a customer's order is not shipped on time is 0.10.
So the probability that a customer's order is shipped on time is:
![1-0.10=0.90](https://tex.z-dn.net/?f=1-0.10%3D0.90)
It is given that we need to consider independent events.
So the probability that all are shipped on time is:
![0.90\times 0.90\times 0.90=0.729](https://tex.z-dn.net/?f=0.90%5Ctimes%200.90%5Ctimes%200.90%3D0.729)
Hence, the probability that all are shipped on time is 0.729
Answer:
6
Step-by-step explanation:
The answer is 6 because there is three other couples and so Barbie would have shaken each couples hand and in a couple there are two people so that would be two handshakes per couple minus Kens hand.