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Troyanec [42]
3 years ago
14

Selec*t the shape bel*ow that has exactl*y two lines of symmetry as well as 180 rotation symmetry.

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0
2 and 3 are the correct ones
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Simplify this math problem show Your work
loris [4]

9514 1404 393

Answer:

  (p -9q)/(4p² +12pq)

Step-by-step explanation:

The least common denominator will be the product of the denominators.

  \dfrac{-3}{4p}+\dfrac{1}{p+3q}=\dfrac{-3(p+3q)+1(4p)}{(4p)(p+3q)}=\boxed{\dfrac{p-9q}{4p^2+12pq}}

5 0
2 years ago
Round 8,088 to the nearest thousand
GalinKa [24]
8,088 rounds to 8,000 to the nearest thousand.
3 0
3 years ago
Read 2 more answers
According to a Pew Research Center, in May 2011, 35% of all American adults had a smart phone (one which the user can use to rea
Veronika [31]

Answer:

p_v =P(z>1.82)=0.034  

Assuming a standard significance level of \alpha=0.05 the best conclusion for this case would be:

4. There is not enough evidence to show that more than 35% of community college students own a smart phone (P-value = 0.034).

Because p_v

If we select a significance level lower than 0.034 then the conclusion would change.

Step-by-step explanation:

Data given

n=300 represent the random sample taken

X=120 represent the people who have a smart phone

\hat p=\frac{120}{300}=0.4 estimated proportion of people who have a smart phone

p_o=0.35 is the value that we want to test

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to test the claim that the true proportion of people who have a smart phone is higher than 0.35, the system of hypothesis are.:  

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.35}{\sqrt{\frac{0.35(1-0.35)}{300}}}=1.82  

Statistical decision  

Since is a right tailed test the p value would be:  

p_v =P(z>1.82)=0.034  

Assuming a standard significance level of \alpha=0.05 the best conclusion for this case would be:

4. There is not enough evidence to show that more than 35% of community college students own a smart phone (P-value = 0.034).

Because p_v

If we select a significance level lower than 0.034 then the conclusion would change.

4 0
3 years ago
Karen’s batting average was 0.444 she was at bat 45 times. How many hits did she get ?
Luden [163]
The answer is that she would have been up to bat 19 times
8 0
3 years ago
Slove for t : /3t - 6/=12​
koban [17]

Answer:

6 or -2

Step-by-step explanation:

|3t - 6| = 12

3t - 6 = 12

3t = 18

t = 6

3t - 6 = -12

3t = -6

t = -2

4 0
1 year ago
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