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AURORKA [14]
3 years ago
11

Most individuals are aware of the fact that the average annual repair cost for an automobile depends on the age of the automobil

e. A researcher is interested in finding out whether the variance of the annual repair costs also increases with the age of the automobile. A sample of 26 automobiles 4 years old showed a sample standard deviation for annual repair costs of $120 and a sample of 23 automobiles 2 years old showed a sample standard deviation for annual repair costs of $100. Let 4 year old automobiles be represented by population 1.State the null and alternative versions of the research hypothesis that the variance in annual repair costs is larger for the older automobiles.
Mathematics
1 answer:
o-na [289]3 years ago
8 0

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Most individuals are aware of the fact that the average annual repair cost for an automobile depends on the age of the automobile. A researcher is interested in finding out whether the variance of the annual repair costs also increases with the age of the automobile. A sample of 26 automobiles 4 years old showed a sample standard deviation for annual repair costs of $120 and a sample of 23 automobiles 2 years old showed a sample standard deviation for annual repair costs of $100. Let 4 year old automobiles be represented by population 1.

State the null and alternative versions of the research hypothesis that the variance in annual repair costs is larger for the older automobiles.

At a 0.01 level of significance, what is your conclusion? What is the p-value?

Answer:

Null hypotheses = H₀ = σ₁² ≤ σ₂²

Alternative hypotheses = Ha = σ₁² > σ₂²

Test statistic = 1.44

p-value = 0.1954

0.1954 > 0.01

Since the p-value is greater than the given significance level therefore, we cannot reject the null hypothesis.

We can conclude that there is no sufficient evidence to support the claim that the variance in annual repair costs is larger for older automobiles.

Step-by-step explanation:

Let σ₁² denotes the variance of 4 years old automobiles

Let σ₂² denotes the variance of 2 years old automobiles

State the null and alternative hypotheses:

The null hypothesis assumes that the variance in annual repair costs is smaller for older automobiles.

Null hypotheses = H₀ = σ₁² ≤ σ₂²

The alternate hypothesis assumes that the variance in annual repair costs is larger for older automobiles.

Alternative hypotheses = Ha = σ₁² > σ₂²

Test statistic:

The test statistic is given by

Test statistic = σ₁²/σ₂²

Test statistic = 120²/100²

Test statistic = 1.44

p-value:

The degree of freedom corresponding to 4 years old automobiles is given by

df₁ = n - 1  

df₁ = 26 - 1  

df₁ = 25

The degree of freedom corresponding to 2 years old automobiles is given by

df₂ = n - 1  

df₂ = 23 - 1  

df₂ = 22

Using Excel to find out the p-value,  

p-value = FDIST(F-value, df₁, df₂)

p-value = FDIST(1.44, 25, 22)

p-value = 0.1954

Conclusion:

When the p-value is less than the significance level then we reject the Null hypotheses

p-value < α   (reject H₀)

But for the given case,

p-value > α

0.1954 > 0.01

Since the p-value is greater than the given significance level therefore, we cannot reject the null hypothesis.

We can conclude that there is no sufficient evidence to support the claim that the variance in annual repair costs is larger for older automobiles.

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Complete the solution of the equation. Find<br> the value of y when x equals -4.<br> x + 3y = 14
LekaFEV [45]

Answer:

y = 6

Step-by-step explanation:

-4 + 3y = 14

+4            +4

3y = 18

----   ----

3      3

y = 6

4 0
3 years ago
A survey was conducted to determine the amount of time, on average, during a given week SCAD students spend outside of class on
fiasKO [112]

Answer:

Standard Deviation = 5.928

Step-by-step explanation:

a) Data:

Days  Hours spent  (Mean - Hour)²

1              5                61.356

2             7                34.024

3            11                  3.360

4           14                   1.362

5           18               26.698

6          22               84.034

6 days 77 hours,    210.834

mean

77/6 = 12.833    and 210.83/6 =  35.139

Therefore, the square root of 35.139 = 5.928

b) The standard deviation of 5.928 shows how the hours students spend outside of class on class work varies from the mean of the total hours they spend outside of class on class work.

5 0
3 years ago
Can you solve the equation 2/3(4x - 5)= 8 by using the division property of equality? explain.
bija089 [108]

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8 0
3 years ago
Observa los puntajes de las respuestas de una evaluación que tuvo de 100 preguntas. Si Alfredo contestó correctamente 57 pregunt
n200080 [17]

La pregunta está incompleta:

Observa los puntajes de las respuestas de una evaluación que tuvo de 100 preguntas. Si Alfredo contestó correctamente 57 preguntas, 16 incorrectas y el resto las dejó en blanco, ¿qué puntuación obtuvo en la evaluación?

Puntos por respuesta:

Correctas: 4

En blanco: -1

Incorrectas: -3

Answer:

Alfredo obtuvo una puntuación de 153.

Step-by-step explanation:

De acuerdo a la información proporcionada, conoces el número de preguntas en la evaluación y el número de preguntas que Alfredo contestó de forma correcta e incorrecta y tienes que restar estas del total de preguntas para encontrar el número de preguntas que dejó en blanco:

100-57-16=27

Ahora, debes multiplicar el número de respuestas correctas, incorrectas y en blanco por su respectivo puntaje:

Correctas: 57*4=228

En blanco: 27*(-1)=-27

Incorrectas: 16*(-3)=-48

Finalmente, debes sumar los resultados obtenidos por cada tipo de respuesta:

228+(-27)+(-48)= 228-27-48=153

De acuerdo a esto, la respuesta es que Alfredo obtuvo una puntuación de 153.

4 0
2 years ago
Express 80 inches in standard notation using feet and inches.
Vladimir79 [104]

80 inches in standard notation using feet and inches would be expressed as 6 ft 8 inches by converting inches into feet and inches.

The solution to the given problem is to use some standard conversion units that are:

  • 1 foot = 12 inches
  • 1 inch = 0.8333 feet

Solution:

As mentioned above that one inch is equal to 0.8333 foot therefore

1 foot = 12 inches

then,

80 inches would be equal to

= \frac{80}{12} ft

= \frac{20}{3} ft

= 6ft 8 inches

= 6' 8"

Thus, 80 inches in standard notation using feet and inches would be expressed as 6 ft 8 inches by converting inches into feet and inches.

Learn more:

brainly.com/question/884268

3 0
3 years ago
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