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nirvana33 [79]
3 years ago
5

Describe the motion of charges from one terminal of a battery to the other through a flashlight.

Physics
1 answer:
Blababa [14]3 years ago
3 0
The DC current leaves one terminal, travels through the switch and goes into the bulb.  There it drops its voltage across the bulb and releases the electric potential energy in the form of light and heat.  (in conventional bulbs most of this energy is heat which is why LEDs are more efficient).  Then the charges that comprise the current are at ground potential and return to the battery.
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Consider a bicycle wheel to be a ring of radius 30 cm and mass 1.5 kg. Neglect the mass of the axle and sprocket. If a force of
Charra [1.4K]

To solve the problem it is necessary to apply the Torque equations and their respective definitions.

The Torque is defined as,

\tau = I \alpha

Where,

I=Inertial Moment

\alpha = Angular acceleration

Also Torque with linear equation is defined as,

\tau = F*d

Where,

F = Force

d= distance

Our dates are given as,

R = 30 cm = 0.3m

m = 1.5 kg

F = 20 N

r = 4.0 cm = 0.04 m

t = 4.0s

Therefore matching two equation we have that,

d*F = I\alpha

For a wheel the moment inertia is defined as,

I= mR2, replacing we have

d*F= \frac{mR^2a}{R}

d*F= mRa

a = \frac{rF}{ mR}

a = \frac{0.04*20}{1.5*0.3}

a=1.77 m/s^2

Then the velocity of the wheel is

V = a *t \\V=1.77*4 \\V=7.11 m/s

Therefore the correct answer is D.

4 0
3 years ago
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Answer:

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Explanation:

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