Answer:
I = 8.75 kg m
Explanation:
This is a rotational movement exercise, let's start with kinetic energy
K = ½ I w²
They tell us that K = 330 J, let's find the angular velocity with kinematics
w² = w₀² + 2 α θ
as part of rest w₀ = 0
w = √ 2α θ
let's reduce the revolutions to the SI system
θ = 30.0 rev (2π rad / 1 rev) = 60π rad
let's calculate the angular velocity
w = √(2 0.200 60π)
w = 8.683 rad / s
we clear from the first equation
I = 2K / w²
let's calculate
I = 2 330 / 8,683²
I = 8.75 kg m
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Answer:
The force when θ = 33° is 1.7625 times of the force when θ = 18°
Explanation:
The force on a moving charge through a magnetic field is given by
F = qvB sin θ
q = charge of the moving particle
v = Velocity of the moving charge
B = Magnetic field strength
θ = angle between the magnetic field and the velocity (direction of the motion) of the moving charge
Because qvB are all constant, we can call the expression K.
F = K sinθ
when θ = 18°,
F = K sin 18° = 0.309K
when θ = 33°, let the force be F₁
F₁ = K sin 33° = 0.5446K
(F₁/F) = (0.5446K/0.309K) = 1.7625
F₁ = 1.7625 F
Hope this Helps!!!
Law of conservation of mass
