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2 years ago

. What type of stress is tension and at what type of plate boundary is it found?

2 answers:

7 0

The three main types of stress go along with the three types of plate boundaries: compression is common at convergent boundaries, tension at divergent boundaries, and shear at transform boundaries. Hope this helps

AveGali [126]2 years ago

3 0

The type of stress is called shear and is found at divergent plate boundaries.

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A well is pumped at Q = 300 m3 /hr in a confined aquifer. The aquifer transmissivity is 25 m2 /hr and the storage coefficient is

Effectus [21]

Answer:

(a). The draw-down at a distance 200 m from the well after pumping for 50 hr is 5.383 m.

(b). The draw-down at a distance 200 m from the well after pumping for 50 hr is 6.707 m.

Explanation:

Given that,

Energy $Q=300\ m^3/hr$

Transmissivity $T = 25\ m^2/hr$

Storage coefficient $S=2.5\times10^{-4}$

Distance r= 200 m

We need to calculate the draw-down at a distance 200 m from the well after pumping for 50 hr

Using formula of draw-down

$s= \dfrac{Q}{4\pi T}(-0.5772-ln\dfrac{r^2S}{4tT})$

Put the value into the formula

$s=\dfrac{300}{4\pi\times25}(-0.5772-ln\dfrac{(200)^2\times2.5\times10^{-4}}{4\times25\times50})$

$s=5.383\ m$

We need to calculate the draw-down at a distance 200 m from the well after pumping for 200 hr

Using formula of draw-down

$s= \dfrac{Q}{4\pi T}(-0.5772-ln\dfrac{r^2S}{4tT})$

Put the value into the formula

$s=\dfrac{300}{4\pi\times25}(-0.5772-ln\dfrac{(200)^2\times2.5\times10^{-4}}{4\times25\times200})$

$s=6.707\ m$

Hence, (a). The draw-down at a distance 200 m from the well after pumping for 50 hr is 5.383 m.

(b). The draw-down at a distance 200 m from the well after pumping for 200 hr is 6.707 m.

3 0

3 years ago

At the end of a race a runner decelerates from a velocity of 11.00 m/s at a rate of 0.300 m/s2. (a) how far does she travel in t

inessss [21]

given that initial velocity is

$v_i = 11 m/s$

deceleration is given as

$a = -0.3 m/s^2$

now we have to find the distance covered in 16 s

$d = v_i * t + \frac{1}{2} at^2$

$d = 11*16 - \frac{1}{2}*0.3*16^2$

$d = 137.6 m$

so it will cover 137.6 m distance

part b)

in order to find the final speed

$v_f = v_i + at$

$v_f = 11 - 0.3*16$

$v_f = 6.2 m/s$

so its speed will be 6.2 m/s

8 0

2 years ago

ASK YOUR TEACHER A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 51.5-gram mass is attach

Simora [160]

Answer:

0.114 kg or 114 g

Explanation:

From the diagram attaches,

Taking the moment about the fulcrum,

sum of clockwise moment = sum of anticlockwise moment.

Wd = W'd'

Where W = weight of the mass, W' = weight of the meter rule, d = distance of the mass from the fulcrum, d' = distance of the meter rule.

make W' the subject of the equation

W' = Wd/d'................ Equation 1

Given: W = mg = 0.0515(9.8) = 0.5047 N, d = (39.2-16) = 23.2 cm, d' = (49.7-39.2) = 10.5 cm

Substitute these values into equation 1

W' = 0.5047(23.2)/10.5

W' = 1.115 N.

But,

m' = W'/g

m' = 1.115/9.8

m' = 0.114 kg

m' = 114 g

6 0

2 years ago

How o astronomers gather information to establish the hubble law?

Novay_Z [31]

<span>they had originally used einsteins therory of relativity and his field equations to figure out their information</span>

8 0

2 years ago

Which of the following does not accurately transistors

seropon [69]

Both NPN and PNP transistors consist of a base composed of an N-type material.

4 0

2 years ago

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