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Scrat [10]
4 years ago
14

the marching band ordered 17 pizzas for a party. each party had 8 slices. lisa ate 7 of the slices. how many slices were left fo

r the rest of the band?
Mathematics
2 answers:
Vedmedyk [2.9K]4 years ago
7 0

There should be 129 slices left in total for the band. Buut in the box that Lisa ate form there should only be 1 slice left

Fofino [41]4 years ago
6 0
1 slice of pizza left
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Simplify <br> (2x - 5)(x + 3) = 0
kirza4 [7]

Answer:

x = 5/2, -3

or

x = 2.5, -3

or

2 1/2, -3

Step-by-step explanation:

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3 years ago
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SUPREME COURT The first Chief Justice of the U.S. Supreme Court, John Jay, served 2079 days
sashaice [31]

Answer:

John Roberts must serve a minimum of 12, 543 days to surpass John Mrshall's record of justice.

Step-by-step explanation:

John Marshall = 2079 + 10, 463 = 12, 542 days

Now, we have to add 1 more day to pass John Marshall because if we do not, we would only be on the same level as John Marshall and NOT EXCEEDING him.

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3 years ago
Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are
Svetlanka [38]

Answer:

(a) Number of sets B given that

  • A⊆B⊆C: 2¹⁰.  (That is: A is a subset of B, B is a subset of C. B might be equal to C)
  • A⊂B⊂C: 2¹⁰ - 2.  (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

<h3>(a)</h3>

Let x_1, x_2, \cdots, x_{20} denote the 20 elements of set X.

Let x_1, x_2, \cdots, x_{10} denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain x_1, x_2, \cdots, x_{10}.

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from x_1, x_2, \cdots, x_{20}.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves 2^{10} -2 = 1024 - 2 = 1022 possibilities.

<h3>(b)</h3>

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's 2^{20} = 1048576 possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only 2^{20} - 2^{10} possibilities left.

5 0
3 years ago
Multiple choice please please answer
lakkis [162]

Answer:

\purple { \boxed{x = 25 \times  \sin \: 39 \degree}}

Step-by-step explanation:

\sin \: 39 \degree =  \frac{x}{25}  \\ 25 \times  \sin \: 39 \degree = x \\  \huge \red{ \boxed{x = 25 \times  \sin \: 39 \degree}}

4 0
3 years ago
A. What is the volume, in cubic feet, of the box in the diagram?
Allisa [31]

Volume is a three-dimensional scalar quantity. The number of boxes that can fit in the cargo hold of the truck is 54.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

The volume of the box = Volume of the cube = a³ = (2.50)³ = 15.625 ft³

The volume of cargo hold = 7.50 × 7.50 × 15 = 843.75 ft³

Now, the number of boxes that can fit in the cargo hold of the truck will be,

Number of boxes = (Volume of truck container)/(Volume of box)

                              = 843.75/15.625

                              = 54

Hence, the number of boxes that can fit in the cargo hold of the truck is 54.

Learn more about Volume:

brainly.com/question/13338592

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5 0
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