All categories

3 years ago

Plz helps me I don’t get these I’m hoping for a smart math helper

Mathematics

2 answers:

fenix001 [56]3 years ago

8 0

1) since the probability of garden is 3/20, the total number of cards has to be a multiple of ten. 10 and 20 do not work, but 30 does. number 1 is 30

2) since the odds are 2/5, they're had to be 2/5*30=12

3) since the odds are3/10, there are 3/10*30=9

4)

mafiozo [28]3 years ago

6 0

probability of building + probability of garden + probability of monument = 1

2/5 + 3/10 + x = 1

2(2) + 1(3) + 10(x) =10(1)

4 + 3 + 10x =10

10x = 3

x =3/10

Total cards (c) x probability of monument (3/10) = # of monument cards (9)

3/10c = 9

c = 9(10/3)

c = 30 Total postcards in the box

Total cards (30) x probability of building (2/5) = # of building cards (b)

30 x 2/5 = b

12 = b number of building postcards

Total cards (30) x probability of garden (3/10) = # of garden cards (g)

30 x 3/10 = g

9 = g number of garden postcards

Answers: 30 postcards, 12 building cards, 9 garden cards

Total cards (c) x probability of building (2/5) = # of building cards (12 + 8)

c (2/5) = 20

c = 20(5/2)

c = 50

****************************************************************************************

Total cards (50) x probability of garden (3/10) = # of garden cards (g)

50 (3/10) = g

15 = g

There were 9 garden cards and now there are 15

*****************************************************************************************

Total cards (50) x probability of monument (3/10) = # of monument (m)

50 (3/10) = m

15 = m

There were 9 monument cards and now there are 15 cards

Answer: 6 more garden and 6 more monument postcards

You might be interested in

h(t)=(t+3) 2 +5 h, left parenthesis, t, right parenthesis, equals, left parenthesis, t, plus, 3, right parenthesis, squared, plu

lesya692 [45]

Answer:

Step-by-step explanation:

If I understand the question right, G(t) = -((t-1)^2) + 5 and we want to solve for the average rate of change over the interval −4 ≤ t ≤ 5.

A function for the rate of change of G(t) is given by G'(t).

G'(t) = d/dt(-((t-1)^2) + 5). We solve this by using the chain rule.

d/dt(-((t-1)^2) + 5) = d/dt(-((t-1)^2)) + d/dt(5) = -2(t-1)*d/dt(t-`1) + 0 = (-2t + 2)*1 = -2t + 2

G'(t) = -2t + 2

This is a linear equation, and the average value of a linear equation f(x) over a range can be found by (f(min) + f(max))/2.

So the average value of G'(t) over −4 ≤ t ≤ 5 is given by ((-2(-4) + 2) + (-2(5) + 2))/2 = ((8 + 2) + (-10 + 2))/2 = (10 - 8)/2 = 2/2 = 1

Click to let others know, how helpful is it

3 0

3 years ago

Find the derivative of the function. y = sin−1(6x + 1)

liraira [26]

If you don't know the derivative of the inverse of sine, you can use implicit differentiation. Apply sine to both sides:

$y=\sin^{-1}(6x+1)\implies\sin y=6x+1$

(true for y between -π/2 and π/2)

Now take the derivative of both sides and solve for it:

$\cos y\dfrac{\mathrm dy}{\mathrm dx}=6$

$\dfrac{\mathrm dy}{\mathrm dx}=6\sec y$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac6{\cos\left(\sin^{-1}(6x+1)\right)}$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac6{\sqrt{1-(6x+1)^2}}$

7 0

3 years ago

If a prius cost $65 per day and civic cost $52 per day. Which will be cheaper?

denis23 [38]

The civic? Is there more to the question?

8 0

3 years ago

A rectangular garden has a walkway around it. The area of the garden is 4(6.5x+3.5). The combined area of the garden and the w

alexdok [17]

Answer:The area of the walkway around is 26 x + 16 as the sum of two terms

Step-by-step explanation:

3 0

3 years ago

Whenever she visits Oakdale, Karin has to drive 55 kilometres due north from home. Whenever she visits Brookfield, she has to dr

Natalija [7]

Sorry it is a bit messy but the answer is right

6 0

3 years ago

Read 2 more answers