Answer:
((2 x + 1) (4 x^2 - 2 x + 1))/8
Step-by-step explanation:
Factor the following:
x^3 + 1/8
Put each term in x^3 + 1/8 over the common denominator 8: x^3 + 1/8 = (8 x^3)/8 + 1/8:
(8 x^3)/8 + 1/8
(8 x^3)/8 + 1/8 = (8 x^3 + 1)/8:
(8 x^3 + 1)/8
8 x^3 + 1 = (2 x)^3 + 1^3:
((2 x)^3 + 1^3)/8
Factor the sum of two cubes. (2 x)^3 + 1^3 = (2 x + 1) ((2 x)^2 - 2 x + 1^2):
((2 x + 1) ((2 x)^2 - 2 x + 1^2))/8
1^2 = 1:
((2 x + 1) ((2 x)^2 - 2 x + 1))/8
Multiply each exponent in 2 x by 2:
((2 x + 1) (2^2 x^2 - 2 x + 1))/8
2^2 = 4:
Answer: ((2 x + 1) (4 x^2 - 2 x + 1))/8
Answer:
Area of composite figure = 216 cm²
Hence, option A is correct.
Step-by-step explanation:
The composite figure consists of two figures.
1) Rectangle
2) Right-angled Triangle
We need to determine the area of the composite figure, so we need to find the area of an individual figure.
Determining the area of the rectangle:
Given
Length l = 14 cm
Width w = 12 cm
Using the formula to determine the area of the rectangle:
A = wl
substituting l = 14 and w = 12
A = (12)(14)
A = 168 cm²
Determining the area of the right-triangle:
Given
Base b = 8 cm
Height h = 12 cm
Using the formula to determine the area of the right-triangle:
A = 1/2 × b × h
A = 1/2 × 8 × 12
A = 4 × 12
A = 48 cm²
Thus, the area of the figure is:
Area of composite figure = Rectangle Area + Right-triangle Area
= 168 cm² + 48 cm²
= 216 cm²
Therefore,
Area of composite figure = 216 cm²
Hence, option A is correct.
Dependent, because you're changing the probability
Answer:
x ≈ {0.653059729092, 3.75570086464}
Step-by-step explanation:
A graphing calculator can tell you the roots of ...
f(x) = ln(x) -1/(x -3)
are near 0.653 and 3.756. These values are sufficiently close that Newton's method iteration can find solutions to full calculator precision in a few iterations.
In the attachment, we use g(x) as the iteration function. Since its value is shown even as its argument is being typed, we can start typing with the graphical solution value, then simply copy the digits of the iterated value as they appear. After about 6 or 8 input digits, the output stops changing, so that is our solution.
Rounded to 6 decimal places, the solutions are {0.653060, 3.755701}.
_____
A similar method can be used on a calculator such as the TI-84. One function can be defined a.s f(x) is above. Another can be defined as g(x) is in the attachment, by making use of the calculator's derivative function. After the first g(0.653) value is found, for example, remaining iterations can be g(Ans) until the result stops changing,
