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yawa3891 [41]
3 years ago
7

How many combinations are possible for 13 objects taken 6 at a time? 1,716 205,920 1,235,520 4,826,809

Mathematics
2 answers:
Zepler [3.9K]3 years ago
9 0

its not C . just took the quiz and it was wrong

                           

nika2105 [10]3 years ago
3 0
The answer would be 1,235,520. To find this you would have to multiply the first six terms following 13.
13!= 13 x 12 x 11 x 10 x 9 x 8

If it wasn't specifically asking for only 6 terms, every number from 13 to 1 would be multiplied.
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Solve the problem 10-5h+2=32
Yuri [45]
First you would add any numbers or variables (x) on each sides. So the equation would look like this -5h+12=32. Then you subtract 12 from both side because you are trying to find what H is; thus making the equation look like this, -5h=20. Then you can divide by -5 and the answer would be h=-4. You can plug it back into the equation to make sure it is correct. 10-5(-4)+2=32
10+20+2=32
32=32
It works.
4 0
3 years ago
Please help! (100 points!) look at the image :)
viva [34]

Answer:

Step-by-step explanation:

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Can anyone please help me I really need your help.
riadik2000 [5.3K]
Wouldn't it be divided, I'm pretty sure it would be, if not I'm sorry
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3 years ago
2x + y + z when x= -2 and y=3 z=5
ruslelena [56]

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4 years ago
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Find the volume of the solid generated by revolving the region bounded by the graphs of the equations and inequalities about the
I am Lyosha [343]

Answer:

The Volume of the solid

V = π(1365.33) cubic units

Step-by-step explanation:

<em>Step(I)</em>:-

Given curves are  x²- y² = 64 ,  x=0 , y=-8 and y=8

The given function   x = f(y)

                            x²- y² = 64

                            x² = y² +64

The Volume of the solid generating by revolving the region bounded by the graphs of the equations

V = \pi \int\limits^a_b {x^2} \, dx

<em>Step(ii</em>):-

the limits are  y = a = -8 and y = b=8

The Volume of the solid

              V =\pi \int\limits^8_8 {(y^2+64)} \, dx

               V = \pi (\frac{y^{3} }{3} + 64 y  )_{-8} ^{8}

              V = \pi (\frac{(8)^{3} }{3} + 64 (8) -  (\frac{(-8)^{3} }{3} +64(-8) )

             V = \pi (\frac{(8)^{3} }{3} + 64 (8) -  (\frac{(-8)^{3} }{3} +64(-8) )  = \pi (\frac{1024}{3} + 1024)

V = π(1365.33) cubic units





5 0
3 years ago
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