Answer:
We are given a equation as:
5log(x+3)=5
We are asked to find a graph that is used to solve the above equation.
We can write the given equation as:
we will divide both side of the equation by 5 to obtain:
log(x+3)=1
Now we have to determine which graph represents the function:
y=log(x+3)
since we know that when x=-2.
y=log(-2+3)=log(1)=0
Hence, the graph should pass through (-2,0).
Hence, the graph that satisfies this is attached to the answer.
Step-by-step explanation:
Alright so your budget is 154 so that already means you cant spend more than
$154. So the uniform is $12 so the inequality could start as:
154 is less than or equal to 12 plus the number of karate classes, which would be;
154 ≤ 12 + 8c
so the answer is B
B. 154 ≤ 12 + 8c
If I helped please mark as brainliest thanks.
Answer:
<em>firstly</em><em> find</em><em> the</em><em> gradient</em><em> given</em><em> by</em><em> the</em><em> equation</em>
<em>m=</em><em>y2-y1</em><em>/</em><em>x2-x1</em>
<em>in this </em><em>case</em><em> </em><em>x1 </em><em>is </em><em>-</em><em>1</em><em>2</em><em>,</em><em>x2 </em><em>is </em><em>-</em><em>1</em><em>7</em><em>,</em><em> </em><em>y1 </em><em>is </em><em>-8 </em><em>and </em><em>y2 </em><em>is</em><em>-</em><em>1</em><em>6</em>
<em>m=</em><em>-</em><em>1</em><em>6</em><em>+</em><em>8</em><em>/</em><em>-</em><em>1</em><em>7</em><em>+</em><em>1</em><em>2</em>
<em> </em><em> </em><em> </em><em>=</em><em>-</em><em>8</em><em>/</em><em>-</em><em>5</em><em> </em><em>or1.</em><em>6</em>
<em>then</em><em> </em><em>use </em><em>the </em><em>equation</em>
<em>y-y1</em><em>=</em><em>m(</em><em>x-x1</em><em>)</em>
y+8=1.6(x+12)
y+8=1.6x+19.2
y=1.6x+11.2
I hope this helps and sorry if it's wrong
Answer:
The exception is 1
Step-by-step explanation:
The cube root of 1 is 1, and the square root of 1 is also 1..
hence, 1 has cube root equal to square root