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3 years ago

FOR A FUNDRAISER THE BASKETBALL TEAM IS SELLING 75 WRIST BANDS FOR $3 EACH

Mathematics

2 answers:

ryzh [129]3 years ago

8 0

Answer:&225

Step-by-step explanation:

Len [333]3 years ago

4 0

Answer:

225

Step-by-step explanation:

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11. Write the balanced equation for the reaction of HC2H3O2, with Al(OH)3 to form H2O and Al(C2H302)3:

Kamila [148]

Answer:

74.36 g of aluminium acetate.

730.27g of aluminium acetate.

- to the nearest hundredth.

Step-by-step explanation:

Acetic acid is usually written as CH3COOH.

a. 6CH3COOH + Al(OH)3 ---> Al(CH3COO)3 + 9H2O

So 6 moles of acetic acid produce 1 mole of aluminium acetate.

Using the molecular masses

6*( 1.008*4 + 12.011*2 + 16 *2) g acetic acid gives (26.98+3(36.032+ 2*12.011)

348.228 g acetic acid gives 207.142 g Al acetate.

So 125 g gives (207.142 / 348.228) * 125

= 74.36 g of aluminium acetate.

(26.98 + 3*16 + 3 * 1.008) g of Al(OH)3 gives 207.142 g Al acetate

78.004 g gives 207.142 g Al acetate

275 g gives (207.142 / 78.004) * 275

= 730.27g Al acetate.

7 0

3 years ago

Solve for x 9(x-1) = 2

Katen [24]

Answer: x = 9/11

Step-by-step explanation:

First, distribute 9 to x and -1

9x - 9 = 2

Then add 9 to both sides

9x = 11

Then divide both sides by 9

x = 9/11

Hope it helps :)

4 0

3 years ago

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago

Find the value of x.<br> 105°/15x

Natalija [7]

$\text{The two angles are supplementary, so their measures add up to 180 degrees.}$

$~~~~~~15x+105 = 180\\\\\implies 15x = 180 -105\\\\\implies 15x = 75\\\\\implies x =\dfrac{75}{15}\\\\\implies x = 5$

8 0

2 years ago

Angie and Kenny play online video games. Angie buys 2 software packages and 3 months of game play. Kenny buys 1 software package

Natali [406]

<span>$15 Write down some equations that express what you know. A = 2*30 + 3x K = 1*30 + 5x A+K = 210 Substitute the expression for A in the A+K=210 expression 2*30 +3x + K = 210 Now substitute the expression for for K 2*30 + 3x + 1*30 + 5x = 210 Multiply and combine terms 60 + 3x + 30 + 5x = 210 90 + 8x = 210 Subtract 90 from both sides 8x = 120 Divide both sides by 8 x = 120/8 = 15 The cost of one month of game play is $15</span>

3 0

3 years ago