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Black_prince [1.1K]
2 years ago
14

Please help I’ll mark you as brainliest if correct!

Mathematics
1 answer:
Alex73 [517]2 years ago
6 0
6ft and 3 inches is 190.5cm
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i just missed a couple says of school and i need someone to explain how to do this to me: please help
algol [13]
Remember the formula y = mx+b.

'm' in mx is the slope.

'b' is the y-intercept.

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The slope is -3. The y-intercept is -3.

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3 years ago
In a sample of 400 customers at a fast-food restaurant, it was
damaskus [11]
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3 years ago
Write the DOMAIN of the function in INTERVAL notation
marusya05 [52]

Answer:

The domain is the set of real numbers. In interval form, the domain of f is (-00,000)

Step-by-step explanation:

6 0
2 years ago
Maria would like to leave a tip (t) of at least 15% of her dinner bill (b). Which inequality best could be used to find the amou
mr_godi [17]
First let's define the variables of the problem:
 t: Tip
 b: dinner bill.
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3 0
3 years ago
A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec
zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0
3 years ago
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