The triangle shown is a right triangle. Solve for b.

Write 0.8 repeating as a fraction

Alborosie

The answer is 8/9 i believe.

4 0

3 years ago

Read 2 more answers

Rearrange the formula V = 1 3 πr2h for h. A) h = 3V πr2 B) h = V 3πr2 C) h = 3πr2 V D) h = πr2 3V

stiks02 [169]

Answer:

Option a) $h=\frac{3V}{\pi r^{2} }$

Step-by-step explanation:

The given formula seems to represent the volume of right circular cone. The correct formula is:

$V=\frac{1}{3} \pi r^{2} h$

We have to rearrange the formula for h. This means we have to move h on one side of the formula and all the other variables and constants on the other side of the equation. This can be done as shown below:

$V=\frac{1}{3} \pi r^{2} h\\\\3V=\pi r^{2} h\\\\h=\frac{3V}{\pi r^{2} }$

5 0

4 years ago

Given that the product of two positive integers is 44, and their least common multiple is 22, what is their greatest common divi

swat32

Answer:

2

Step-by-step explanation:

For any positive numbers a,b we always have the following identity:

$a\cdot b=gcd(a,b)\cdot lcm(a,b)$

(gcd(a,b) denotes the greatest common divisor between a and b, and lcm(a,b) denotes the least common multiple between a and b)

In our case, we are given that $a\cdot b = 44$ and that $lcm(a,b)=22$ . Plugging that in into our identity, we get:

$44=gcd(a,b)\cdot 22$

And so solving for $gcd(a,b)$ :

$gcd(a,b)=\frac{44}{22}=2$

5 0

3 years ago

A book had a lenght of 5 inches and a width of 10 inches. What is the area of the book

babunello [35]

Answer:

50

Step-by-step explanation:

7 0

4 years ago

If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by

PIT_PIT [208]

Answer:

The family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

$\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|}$ (1)

Where:

$\theta$ - Angle between vectors, in sexagesimal degrees.

$\|\vec a\|, \|\vec b \|$ - Norms of vectors $\vec {a}$ and $\vec{b}$

If $\theta$ is acute, then the cosine function is bounded between 0 a 1 and if we know that $\vec {a} = (p, 3, -7)$ and $\vec {b} = (p, -p, 4)$ , then the possible values for $p$ are: